Let's solve the IUPAC naming step-by-step for the compound in the image: --- ## **Step 1: Find the Longest Carbon Chain Containing the Aldehyde Group** - The aldehyde group (–CHO) takes priority and must be included in the main chain. - Start numbering from the carbon of the aldehyde group. - Count the carbons: 1. Aldehyde carbon (1) 2. Next to aldehyde (2) 3. Next (3) 4. Next (4) 5. Next (5) 6. Next (6) 7. Next (7) 8. Next (8) **So, there are 8 carbons in the main chain. The parent name is "octanal".** --- ## **Step 2: Identify and Number the Substituents** - Numbering starts at the aldehyde carbon (always position 1). - There is a double bond between carbons 4 and 5 (from the aldehyde). - There is a tert-butyl group attached to carbon 5. --- ## **Step 3: Assign the Location of the Double Bond and Substituent** - The double bond is between C4 and C5, so it is a "4-octenal" (since the double bond starts at C4). - The tert-butyl group is on C5. --- ## **Step 4: Assemble the Name** - The base name is "oct-4-enal" (octanal, with a double bond at position 4). - The substituent is "5-tert-butyl". Combine the parts as per IUPAC rules: **5-tert-butyl-oct-4-enal** --- ## **Final Answer** ### **IUPAC Name:** **5-tert-butyl-oct-4-enal** --- ### **Summary of the Steps:** 1. Find the longest chain with the aldehyde: 8 carbons ("octanal"). 2. Number from the aldehyde; identify double bond at C4, tert-butyl at C5. 3. Construct the name: 5-tert-butyl-oct-4-enal. --- If you need more details or have another example, feel free to ask!