Absolutely, I'll help you step by step! First, let's clarify what you're being asked: > **You want to find the "odds against" a person having A+ blood, using the percentages provided.** But your table is a bit scrambled. Let's try to reconstruct the blood type percentages based on the information you wrote. You listed some numbers—I'll try to match them to standard blood type notation: - AB: 4.5% - B: 7% - A: 36% - O: 52.5% Is this correct? (It matches some common patterns.) Now, usually, blood types are broken down further (A+, A-, O+, O-, etc.), but your question just says **A+** and gives **A** as 36%. **Let’s proceed with what you gave:** ## 1. **Probability of A+** If 36% have type A (assuming this is A+), then: **Probability (P) person has A+ = 36% = 0.36** ## 2. **Probability person does NOT have A+** P(not A+) = 100% - 36% = **64% = 0.64** ## 3. **Odds against having A+** **Odds against** means: > The ratio of the probability that the event does NOT happen to the probability that it DOES happen. So, \[ \text{Odds against A+} = \frac{P(\text{not A+})}{P(\text{A+})} = \frac{0.64}{0.36} \] You can simplify this: \[ \frac{0.64}{0.36} = \frac{64}{36} = \frac{16}{9} \] So, **the odds against a person having A+ blood are 16:9.** --- ## **Summary Table** | Blood Type | Percent | |------------|---------| | A+ | 36% | | Not A+ | 64% | **Odds against A+ = 64:36 = 16:9.** --- ### **What does "odds against" mean?** If you randomly select a person: - For every **16 people who do NOT have A+**, there are **9 who DO** have A+. --- If your data actually separates A+ and A-, or you want to use different numbers, let me know! Is this clear? Would you like to practice with another example?