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Act like a helpful tutor and exlain me : Great question! Let’s work this out step by step ? ### ? Formula for Mass Flow Rate The mass flow rate \(\dot{m}\) is given by: \[ \dot{m} = \rho \cdot A \cdot V \] Where: - \(\rho\) = density of fluid (kg/m³) - \(A\) = cross-sectional area of pipe (m²) - \(V\) = velocity of fluid (m/s) --- ### ? Substitution - \(\rho = 900 \, \text{kg/m}^3\) - \(A = 0.05 \, \text{m}^2\) - \(V = 1.6 \, \text{m/s}\) \[ \dot{m} = 900 \cdot 0.05 \cdot 1.6 \] --- ### ? Calculation \[ \dot{m} = 900 \cdot 0.08 = 72 \, \text{kg/s} \] --- ✅ **Final Answer:** The **mass flow rate** of the liquid is: \[ \boxed{72 \, \text{kg/s}} \] --- Would you like me to also show you how to calculate the **volumetric flow rate** (which is often paired with mass flow rate in fluid mechanics problems)?

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Act like a helpful tutor and exlain me : Great question! Let’s work this out step by step ? ### ? Formula for Mass Flow Rate The mass flow rate \(\dot{m}\) is given by: \[ \dot{m} = \rho \cdot A \cdot V \] Where: - \(\rho\) = density of fluid (kg/m³) - \(A\) = cross-sectional area of pipe (m²) - \(V\) = velocity of fluid (m/s) --- ### ? Substitution - \(\rho = 900 \, \text{kg/m}^3\) - \(A = 0.05 \, \text{m}^2\) - \(V = 1.6 \, \text{m/s}\) \[ \dot{m} = 900 \cdot 0.05 \cdot 1.6 \] --- ### ? Calculation \[ \dot{m} = 900 \cdot 0.08 = 72 \, \text{kg/s} \] --- ✅ **Final Answer:** The **mass flow rate** of the liquid is: \[ \boxed{72 \, \text{kg/s}} \] --- Would you like me to also show you how to calculate the **volumetric flow rate** (which is often paired with mass flow rate in fluid mechanics problems)?

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Asked by: Alok Kumar
Created at: 2026-01-24 03:15:31

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# How to Calculate Volumetric Flow Rate Yes! Let’s walk through how to find the **volumetric flow rate** step by step. --- ## 1. Volumetric Flow Rate Formula The **volumetric flow rate** \( Q \) is given by: \[ Q = A \cdot V \] Where: - \( Q \) = volumetric flow rate (in m³/s) - \( A \) = cross-sectional area of pipe (in m²) - \( V \) = velocity of the fluid (in m/s) --- ## 2. Substituting Your Values Given: - \( A = .05 \, \text{m}^2 \) - \( V = 1.6 \, \text{m/s} \) Plug in the values: \[ Q = .05 \cdot 1.6 \] --- ## 3. Calculation \[ Q = .08 \, \text{m}^3/\text{s} \] --- ## 4. Final Answer \[ \boxed{.08 \, \text{m}^3/\text{s}} \] --- ## 5. Relationship Between Mass and Volumetric Flow Rate Recall from before: \[ \dot{m} = \rho Q \] Where \(\rho\) is the density. Using your previous answers: \[ \dot{m} = 900 \times .08 = 72 \, \text{kg/s} \] This matches your original calculation. --- **Summary Table** | Quantity | Formula | Value | |-------------------------|-------------------------|------------| | Mass flow rate (\(\dot{m}\)) | \(\rho A V\) or \(\rho Q\) | \(72\,\text{kg/s}\) | | Volumetric flow rate (\(Q\)) | \(A V\) | \(.08\,\text{m}^3/\text{s}\) | --- **Let me know if you want more details or examples!**

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