Act like a helpful tutor and exlain me : Great question! Let’s work this out step by step ? ### ? Formula for Mass Flow Rate The mass flow rate \(\dot{m}\) is given by: \[ \dot{m} = \rho \cdot A \cdot V \] Where: - \(\rho\) = density of fluid (kg/m³) - \(A\) = cross-sectional area of pipe (m²) - \(V\) = velocity of fluid (m/s) --- ### ? Substitution - \(\rho = 900 \, \text{kg/m}^3\) - \(A = 0.05 \, \text{m}^2\) - \(V = 1.6 \, \text{m/s}\) \[ \dot{m} = 900 \cdot 0.05 \cdot 1.6 \] --- ### ? Calculation \[ \dot{m} = 900 \cdot 0.08 = 72 \, \text{kg/s} \] --- ✅ **Final Answer:** The **mass flow rate** of the liquid is: \[ \boxed{72 \, \text{kg/s}} \] --- Would you like me to also show you how to calculate the **volumetric flow rate** (which is often paired with mass flow rate in fluid mechanics problems)?
Question:
Act like a helpful tutor and exlain me : Great question! Let’s work this out step by step ? ### ? Formula for Mass Flow Rate The mass flow rate \(\dot{m}\) is given by: \[ \dot{m} = \rho \cdot A \cdot V \] Where: - \(\rho\) = density of fluid (kg/m³) - \(A\) = cross-sectional area of pipe (m²) - \(V\) = velocity of fluid (m/s) --- ### ? Substitution - \(\rho = 900 \, \text{kg/m}^3\) - \(A = 0.05 \, \text{m}^2\) - \(V = 1.6 \, \text{m/s}\) \[ \dot{m} = 900 \cdot 0.05 \cdot 1.6 \] --- ### ? Calculation \[ \dot{m} = 900 \cdot 0.08 = 72 \, \text{kg/s} \] --- ✅ **Final Answer:** The **mass flow rate** of the liquid is: \[ \boxed{72 \, \text{kg/s}} \] --- Would you like me to also show you how to calculate the **volumetric flow rate** (which is often paired with mass flow rate in fluid mechanics problems)?
Asked by: Alok Kumar
Created at: 2026-01-24 03:15:31
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