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Act like a helpful tutor and exlain me : Give step-by-step solution with explanation and final answer:Br aS AS [ )— = Br d.

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Act like a helpful tutor and exlain me : Give step-by-step solution with explanation and final answer:Uploaded ImageBr aS AS [ )— = Br d.

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Asked by: Sagar
Created at: 2025-10-26 01:49:59

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Certainly! Let's the transformation step-by. --- ##Given Reaction:** Starting material: Benzene (C₆H₆) Product: A compound with a benzene ring substituted with a **bromine (Br)** and a **tert-butyl group** (a carbon attached to three methyl groups). --- ## **Step 1: Recognize the Product Structure** The product appears to be **4-bromo-1-tert-butylbenzene**, where: - A benzene ring - Bromine substituent - Tert-butyl group (–C(CH₃)₃) --- ## **Step 2: Understand the Reaction Type** - The reaction involves benzene reacting with a **bromination** process. - The presence of a **tert-butyl group** suggests **electrophilic aromatic substitution** (EAS). --- ## **Step 3: Identify the Reagents and Conditions (Likely)** - To install the tert-butyl group: **Friedel-Crafts alkylation** with **tert-butyl chloride** (or tert-butyl bromide) in the presence of **AlCl₃**. - To brominate the benzene ring: **Electrophilic aromatic substitution** with **bromine (Br₂)**, often in the presence of a **Lewis acid catalyst** like FeBr₃ or FeCl₃. --- ## **Step 4: Step-by-step synthesis** ### **a) Introduction of tert-Butyl Group** - React benzene with **tert-butyl chloride** (or tert-butyl bromide) in presence of **AlCl₃**. - This yields **tert-butylbenzene**, where the tert-butyl group is attached to the benzene ring. ### **b) Bromination of tert-Butylbenzene** - React tert-butylbenzene with **Br₂** and **FeBr₃**. - The **bromine** will substitute a hydrogen on the ring, preferably **para** or **ortho** relative to the tert-butyl group due to its activating effect. - The **tert-butyl group** is an **activating group** and **ortho/para directing**. ### **c) Final Product** - The major product will be **para-bromo-tert-butylbenzene**. --- ## **Final Answer:** The product structure in the image corresponds to **4-bromo-1-tert-butylbenzene**. --- ## **Summary:** - **React benzene** with **tert-butyl chloride** and **AlCl₃** → **tert-butylbenzene**. - **Brominate** with **Br₂ / FeBr₃** → **para-bromo-tert-butylbenzene**. - The final compound shows **bromine** para to **tert-butyl** group on benzene. --- Let me know if you'd like me to elaborate further on any step!

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