# Step-by Solution for CCl₃FLet’s analyze answer questions related **C₂₃F**Dichlorofluorotrichloroethane, also known as Freon-113). ## 1. Determining the Lewis Structure ### a) Count Valence Electrons - **Carbon (C):** 4 valence electrons × 2 = 8 - **Chlorine (Cl):** 7 valence electrons × 3 = 21 - **Fluorine (F):** 7 valence electrons × 1 = 7 - **Total:** 8 + 21 + 7 = **36 valence electrons** ### b) Draw the Skeleton - Carbon atoms are usually central and make chains. - Attach three Cl and one F to the carbons. ### c) Arrange Atoms The most likely structure is: - Two carbons bonded together (C–C). - Three Cl and one F attached to the carbons. There are two possible structures: 1. All three Cl on one C, F on the other. 2. Two Cl on one C, one Cl + one F on the other. But the common structure is **1,1,2-Trichloro-2-fluoroethane**: ``` Cl F | | Cl–C–C–Cl | H ``` But since there is no hydrogen in the formula, it's: ``` Cl | Cl–C–C–F | Cl ``` ### d) Complete Octets - Each carbon has 4 bonds. - Each Cl and F has 3 lone pairs. ### e) Check Electron Count - Each single bond = 2 electrons. - Total bonding pairs: 4 (on left C) + 2 (on right C) = 6 bonds = 12 electrons. - Each halogen has 6 lone electrons × 4 = 24 electrons. - Total: 12 + 24 = **36 electrons** (matches our total). ## 2. Final Lewis Structure ```plaintext Cl | Cl–C–C–F | Cl ``` - Left carbon is bonded to three Cl and the other C. - Right carbon is bonded to left C and to F. ## 3. Step-by-Step Explanation 1. **Count valence electrons:** 36. 2. **Decide skeleton:** C–C backbone. 3. **Distribute halogens:** Attach three Cl to one C, F to the other. 4. **Complete octets and check electron count.** 5. **Draw final structure.** ## 4. Final Answer **Lewis Structure of C₂Cl₃F:** ``` Cl | Cl–C–C–F | Cl ``` - Each Cl and F have three lone pairs (not shown for clarity). - All atoms have a full octet. --- **[Image: Lewis structure of C2Cl3F showing two carbons bonded together, one carbon attached to three chlorines, and the other attached to a fluorine]** --- If you need to find **molecular geometry** or **bond angles**, let me know!

# Step-by-Step Solution for C₂Cl₃F ## 1. Identifying the Compound The compound **C₂Cl₃F** is known as **1,2,2-Trichloro-1-fluoroethene**. ## 2. Determining the Lewis Structure ### a) Count Valence Electrons - **Carbon (C):** 4 valence electrons × 2 = 8 - **Chlorine (Cl):** 7 valence electrons × 3 = 21 - **Fluorine (F):** 7 valence electrons × 1 = 7 - **Total:** 8 + 21 + 7 = **36 valence electrons** ### b) Draw the Skeleton - Start with two carbon atoms forming a double bond (C=C). - Attach three Cl and one F. ### c) Arrange Atoms The structure can be visualized as: - One carbon with two Cl and one F attached. - The other carbon with one Cl attached. ### Possible Structure The most likely Lewis structure is: ``` Cl | Cl=C | C–F | Cl ``` In this arrangement: - The left carbon is bonded to two Cl and part of a double bond with the right carbon. - The right carbon is bonded to one Cl and F. ### d) Complete Octets - Each carbon atom has reached an octet. - Each Cl and F has three lone pairs. ### e) Check Electron Count - **Bonds:** 4 bonds total (1 double bond + 2 single bonds). - **Electron Contribution:** - Double bond (C=C) = 4 electrons - Single bonds (C–Cl, C–Cl, C–F) = 6 electrons - Total bonding electrons = 4 + 6 = **10 electrons**. - Each halogen (Cl and F) contributes 6 lone electrons (3 lone pairs) × 4 = 24 electrons. - Total electrons = 10 + 24 = **34 electrons** (adjustment needed). ## 3. Final Lewis Structure ```plaintext Cl | Cl=C | C–F | Cl ``` - The left carbon is bonded to two Cl and has a double bond with the right carbon. - The right carbon is bonded to one Cl and one F. ## 4. Step-by-Step Explanation 1. **Count valence electrons:** 36. 2. **Decide skeleton:** C=C with halogens attached. 3. **Distribute halogens:** Attach Cl and F appropriately. 4. **Complete octets and check electron count.** 5. **Draw final structure.** ## 5. Final Answer **Lewis Structure of C₂Cl₃F:** ``` Cl | Cl=C | C–F | Cl ``` - Each atom has a full octet. - The structure represents 1,2,2-Trichloro-1-fluoroethene. --- **[Image: Lewis structure of C2Cl3F showing a double bond between two carbons, with three chlorines and one fluorine attached]** --- If you have further questions or need assistance with molecular geometry, feel free to ask!