VIPSolutions logo ✨ VIPSolutions

Act like a helpful tutor and exlain me : Give step-by-step solution with explanation and final answer:The couple A= 18 kN"m acts in a vertical plane with h=70mm and b=25mm. Determine the stress at (a)Aand (b) B - 20 40 20 - b M A 1 = - PF Am ’ i Dimensions in mm

Question:

Act like a helpful tutor and exlain me : Give step-by-step solution with explanation and final answer:Uploaded ImageThe couple A= 18 kN"m acts in a vertical plane with h=70mm and b=25mm. Determine the stress at (a)Aand (b) B - 20 40 20 - b M A 1 = - PF Am ’ i Dimensions in mm

This is AI generated Response.
Asked by: manish kumar
Created at: 2025-10-06 20:32:08

Final Answer:

Rendered Raw Text
Did you like this answer?
Let's break this problem down step by step: --- # Step 1: **Identify the Problem** Given: - Couple \( M = 18 \) kN·m = **18,000 N·m** - Rectangle section with: - \( h = 70 \) mm = **.070 m** - \( b = 25 \) mm = **.025 m** We are to find **the stress at points A and B**. --- # Step 2: **Find the Moment of Inertia (I)** For a rectangle about its centroid (neutral axis): \[ I = \frac{1}{12} b h^3 \] Plugging in the values (convert mm to m): \[ I = \frac{1}{12} \times .025 \times (.070)^3 \] \[ I = \frac{1}{12} \times .025 \times .000343 \] \[ I = \frac{1}{12} \times .000008575 \] \[ I = .0000007146 \ \text{m}^4 \] --- # Step 3: **Bending Stress Formula** Bending stress at a point is: \[ \sigma = \frac{M y}{I} \] Where: - \( M \): Moment (in N·m) - \( y \): Distance from the neutral axis to the point (in meters) - \( I \): Moment of inertia (in m\(^4\)) --- # Step 4: **Find Distance \( y \) for Points A and B** - **Neutral axis** is at the centroid: at \( \frac{h}{2} \) from either edge. - \( y \) is measured from the centroid: - For **point A**: - From centroid to A: \( y_A = \frac{h}{2} - .020 = .035 - .020 = .015 \) m (since centroid is 35 mm from bottom, A is 20 mm above centroid). - For **point B**: - From centroid to B: \( y_B = -\frac{h}{2} = -.035 \) m (since B is at the very bottom, so it's -35 mm from centroid). --- # Step 5: **Calculate Stress at Each Point** ## At Point A \[ \sigma_A = \frac{M y_A}{I} = \frac{18000 \times .015}{.0000007146} \] \[ \sigma_A = \frac{270}{.0000007146} = 3.78 \times 10^8 \ \text{N/m}^2 = 378 \ \text{MPa} \] ## At Point B \[ \sigma_B = \frac{M y_B}{I} = \frac{18000 \times (-.035)}{.0000007146} \] \[ \sigma_B = \frac{-630}{.0000007146} = -8.82 \times 10^8 \ \text{N/m}^2 = -882 \ \text{MPa} \] --- # Step 6: **Interpretation** - **Positive stress**: tension - **Negative stress**: compression --- ## **Final Answers** **(a) At A:** \[ \boxed{\sigma_A = 378 \ \text{MPa} \ \text{(tension)}} \] **(b) At B:** \[ \boxed{\sigma_B = -882 \ \text{MPa} \ \text{(compression)}} \] --- Let me know if you need the calculations double-checked or more explanation on any step!

📢 Instructions:

  • Ask anything relatd to above question only.
  • For new Question goto :

Study Help, Fast Answers

VIPSolutions focuses on clear, step‑by‑step explanations so you can learn quickly. Whether you need an AI‑generated walkthrough or a short hint to get unstuck, each solution is organized for fast reading and easy review later.

Search similar questions, compare approaches, and bookmark the best answers for revision. Our goal is simple: quick, reliable study help that feels natural—not noisy.