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Act like a helpful tutor and exlain me : Give step-by-step solution with explanation and final answer:A round main supply duct will carry an airflow of 2 , 0 0 0 CFM with a static pressure drop of 0 . 3 2 5 3 5 ” w . c . What size duct diameter will each branch be ? Use the Equal Friction Duct Sizing Chart provided below or the PDF version provided in Moodle. Fill in the number of the diameter,100 hc) . : . EEL po, of 6 2 Pir (IN INCHES) yr SEERA Saber 0 RSS Xd ESR ol L111: 77 ooo NTH RHA SSat sa 77 “ Si mas a 8 wl] I NAN NN as Sis EE 102A] SR SEAT ay oe Pratt NAN XY NAS ALTRI Sasa fret i RHR LITRE, Sei gran NE g SHEL a ae RI AEE OSE ' gE [SSH PATA Semi ol JA z

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Act like a helpful tutor and exlain me : Give step-by-step solution with explanation and final answer:A round main supply duct will carry an airflow of 2 , 0 0 0 CFM with a static pressure drop of 0 . 3 2 5 3 5 ” w . c . What size duct diameter will each branch be ? Use the Equal Friction Duct Sizing Chart provided below or the PDF version provided in Moodle. Fill in the number of the diameter,Uploaded Image100 hc) . : . EEL po, of 6 2 Pir (IN INCHES) yr SEERA Saber 0 RSS Xd ESR ol L111: 77 ooo NTH RHA SSat sa 77 “ Si mas a 8 wl] I NAN NN as Sis EE 102A] SR SEAT ay oe Pratt NAN XY NAS ALTRI Sasa fret i RHR LITRE, Sei gran NE g SHEL a ae RI AEE OSE ' gE [SSH PATA Semi ol JA z

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Asked by: manish kumar
Created at: 2025-10-06 08:59:10

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# Step-by-Step Solution: Duct Sizing Using Equal Friction Chart Let's find the required duct diameter for a **main supply duct** that carries **2,000 CFM** with a **static pressure drop** of **.325" w.c./100 ft**. --- ## 1. **Locate the Given Values on the Chart** ### - **Air Flow Rate (CFM):** Find **2,000 CFM** on the bottom horizontal axis. ### - **Friction Loss (inches W.C./100 ft):** Find **.325** on the left vertical axis. This is between **.3** and **.4**. --- ## 2. **Draw a Line Between These Points** - From **2,000 CFM** (bottom axis), draw a vertical line up. - From **.325** (left axis), draw a horizontal line across. - The intersection of these lines is your reference point. --- ## 3. **Find the Corresponding Duct Diameter** - From your intersection point, look **upward** to see which **duct diameter** line it falls on or is closest to (top axis). --- ## 4. **Step-by-Step on the Chart** ### a. **Mark 2,000 CFM** at the bottom. ### b. **Mark .325" W.C./100 ft** at the left. ### c. **Trace up from 2,000 CFM** and **across from .325** until they cross. ### d. **From the intersection**, move **upward** to see the duct diameter. --- ## 5. **Reading the Chart** - The intersection point (2,000 CFM at .325" W.C./100ft) lands **between the 12" and 14" duct diameter lines**. - It is **closer to the 14" line**. --- ## 6. **Final Answer** ### **The required round duct diameter is approximately:** # **14 inches** --- ## **Summary Table** | Parameter | Value | |------------------------|--------------| | Air Flow Rate (CFM) | 2,000 | | Friction Loss (in W.C./100 ft) | .325 | | Duct Diameter (inches) | **14** | --- ### **Explanation** - This is a standard method using the Equal Friction Duct Sizing Chart. - The answer is **14 inches** for the main round duct carrying 2,000 CFM at .325" W.C./100ft. --- **If you want to size a branch duct or have a different CFM, repeat the same process for that CFM value!** --- **Let me know if you need help with a different airflow or friction loss!**

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