Act like a helpful tutor and exlain me : Give step-by-step solution with explanation and final answer:a rggizs HHT 284s “EREEC $s53% 3%eis fe [2]
Question:
Act like a helpful tutor and exlain me :
Give step-by-step solution with explanation and final answer:a
rggizs
HHT
284s
“EREEC
$s53%
3%eis
fe
[2]
This is AI generated Response.
Asked by: manish kumar
Created at: 2025-10-06 08:56:06
Asked by: manish kumar
Created at: 2025-10-06 08:56:06
Final Answer:
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Let's break down and solve the problem step-by-step.
---
## Problem Restatement
You have a-tube manometer system:
- at point 2 (open to the atmosphere) is ** psi (atmospheric pressure)**.
- You need to find **the pressure at point 1** (over the bit), so the system is in equilibrium (levels are equal).
- The answer is given as **7.5 psi**.
---
## Step 1: Understand the U-Tube Manometer
A U-tube manometer measures pressure difference by the height difference of the fluid in the two arms. The pressure at each end of the U-tube can be written as:
\[
P_1 + \rho_{fluid} g h_1 = P_2 + \rho_{fluid} g h_2
\]
Where:
- \(P_1\), \(P_2\) = pressure at each end (points 1 and 2)
- \(\rho_{fluid}\) = density of the manometer fluid
- \(h_1\), \(h_2\) = heights of fluid columns at each side
For equilibrium and same fluid, the height difference is due to pressure difference.
---
## Step 2: Assign Known Values
From the image and description:
- \(P_2 = \) psi (atmospheric)
- The fluid in the manometer is likely drilling mud or similar (details not specified, but answer provided helps)
- We are to find \(P_1\) required to balance the column.
---
## Step 3: Write the Pressure Balance Equation
Assume the height difference in the U-tube column is \(h\).
Since the fluid is the same on both sides and the open side is at atmospheric pressure:
\[
P_1 = P_2 + \rho_{fluid} g h
\]
But since \(P_2 = \):
\[
P_1 = \rho_{fluid} g h
\]
---
## Step 4: Relate Given Answer to Calculations
The answer is **7.5 psi**. Let's check the units:
1 psi = 6894.76 Pa (N/m²).
So:
\[
7.5\, \text{psi} = 7.5 \times 6894.76 = 51710.7 \, \text{Pa}
\]
If you were given a height and density, you could check this with:
\[
P_1 = \rho g h
\]
But since the answer is given, the key point is **the pressure at point 1 must be 7.5 psi higher than atmospheric** for the column to be level (for equilibrium).
---
## Step 5: Final Answer
### **Final Answer**
> The pressure required at point 1 to equilibrate the system is **7.5 psi**.
---
### **Explanation**
- The U-tube manometer measures the pressure difference between point 1 (over the bit) and point 2 (atmosphere).
- For equilibrium, the pressure at point 1 must exactly balance the pressure due to the column of fluid, which is equivalent to 7.5 psi.
- Therefore, the required pressure at point 1 is **7.5 psi**.
---
If you have more details (height or fluid density), I can show the full calculation; but this is the conceptual process and matches the answer provided.
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