VIPSolutionsAct like a helpful tutor and exlain me : Give step-by-step solution with explanation and final answer:MECHANICAL ENGINEERING Ql. A refrigerator extracts 360 kJ of heat while consuming 120 kJ of work. Find the coefficient of performance (COP). Total = 5 marks
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Give step-by-step solution with explanation and final answer:
MECHANICAL ENGINEERING
Ql. A refrigerator extracts 360 kJ of
heat while consuming 120 kJ of
work. Find the coefficient of
performance (COP).
Total = 5 marks
This is AI generated Response.
Asked by: manish kumar
Created at: 2025-10-05 19:11:41
Asked by: manish kumar
Created at: 2025-10-05 19:11:41
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# Step-by-Step Solution
## **Given Data**
- Heat extracted by refrigerator (\( Q_L \)) = **360 kJ**
- Work input (\( W \)) = **120 kJ**
---
## **Step 1: Write the Formula for COP**
For a refrigerator, the **coefficient of performance (COP)** is defined as:
\[
\text{COP}_{\text{ref}} = \frac{Q_L}{W}
\]
where:
- \( Q_L \): Heat extracted from the cold reservoir (kJ)
- \( W \): Work input to the refrigerator (kJ)
---
## **Step 2: Substitute the Values**
\[
\text{COP}_{\text{ref}} = \frac{360}{120}
\]
---
## **Step 3: Calculate the COP**
\[
\text{COP}_{\text{ref}} = 3
\]
---
## **Final Answer**
\[
\boxed{3}
\]
---
## **Explanation**
- The COP is a measure of how effectively a refrigerator uses work to extract heat from the cold reservoir.
- A COP of 3 means that for every 1 kJ of work supplied, the refrigerator removes 3 kJ of heat.
---
**If you need further clarification or an explanation of what COP means in practical terms, just ask!**
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