# Step-by-Step Solution Let's break down the problem: - **Heat extracted from cold reservoir (Q\_L)**: 300 kJ - **Work input (W)**: 100 kJ - **Asked**: Find the COP (Coefficient of Performance) of the refrigerator --- ## 1. Understand What COP Means For a refrigerator, the **Coefficient of Performance (COP)** is defined as: \[ \text{COP}_{\text{ref}} = \frac{\text{Heat removed from cold reservoir (} Q_L \text{)}}{\text{Work input (} W \text{)}} \] --- ## 2. Plug in the Values Given: - \( Q_L = 300\, \text{kJ} \) - \( W = 100\, \text{kJ} \) \[ \text{COP}_{\text{ref}} = \frac{Q_L}{W} = \frac{300}{100} \] --- ## 3. Calculate COP \[ \text{COP}_{\text{ref}} = \frac{300}{100} = 3 \] --- ## 4. Final Answer **The COP (Coefficient of Performance) of the refrigerator is:** \[ \boxed{3} \] --- ### Summary Table | Quantity | Value (kJ) | |------------------|------------| | \( Q_L \) | 300 | | \( W \) | 100 | | COP | 3 |