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Act like a helpful tutor and exlain me : Give step-by-step solution with explanation and final answer:3. A piston/eylinder initially contains 0.4 m* of air at 100 kPa and 80 °C. The air is then compressed such that the temperature inside the cylinder remains constant. a) Draw the piston/cylinder combination and write the initial properties next to it. b) Determine the work done using the ideal gas assumption. ©) Determine the final pressure (state 2). d) Draw a P-V graph, indicating the two volumes, the initial and final pressures, and an estimate of the pressure curve from the initial state (state 1) to the final state (state 2).

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Act like a helpful tutor and exlain me : Give step-by-step solution with explanation and final answer:Uploaded Image3. A piston/eylinder initially contains 0.4 m* of air at 100 kPa and 80 °C. The air is then compressed such that the temperature inside the cylinder remains constant. a) Draw the piston/cylinder combination and write the initial properties next to it. b) Determine the work done using the ideal gas assumption. ©) Determine the final pressure (state 2). d) Draw a P-V graph, indicating the two volumes, the initial and final pressures, and an estimate of the pressure curve from the initial state (state 1) to the final state (state 2).

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Asked by: manish kumar
Created at: 2025-10-02 11:45:12

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Let's break down and solve each part step by step: --- ## Given Data - **Initial Volume, \( V_1 \) = .4 m³** - **Initial Pressure, \( P_1 \) = 100 kPa** - **Initial Temperature, \( T_1 \) = 80°C = 353.15 K** - **Process:** Isothermal compression (\( T_2 = T_1 \)) - **Final Volume, \( V_2 \):** Not given, but to be left as a variable for now. We'll use the **ideal gas law** throughout. --- a) Draw the Piston/Cylinder and Note Initial Properties ``` |---------------------| | | <--- Movable piston | Air | | V1 = .4 m³ | | P1 = 100 kPa | | T1 = 80°C = 353.15K| |---------------------| ``` *The piston/cylinder contains air at the specified initial state above.* --- ## b) Work Done During Isothermal Compression **For an isothermal (constant temperature) process for an ideal gas:** \[ W = nRT \ln\left(\frac{V_2}{V_1}\right) \] But since temperature is constant, and from the ideal gas law \( P_1 V_1 = P_2 V_2 \): \[ n = \frac{P_1 V_1}{RT_1} \] So, \[ W = nRT \ln\left(\frac{V_2}{V_1}\right) = P_1 V_1 \ln\left(\frac{V_2}{V_1}\right) \] Alternatively, since \( V_2 = \frac{P_1 V_1}{P_2} \): \[ W = P_1 V_1 \ln\left(\frac{P_1}{P_2}\right) \] **Leave \( V_2 \) or \( P_2 \) as unknown for now; will be found in part (c).** --- ## c) Determine the Final Pressure (State 2) Since the temperature is constant: \[ P_1 V_1 = P_2 V_2 \] So, \[ P_2 = \frac{P_1 V_1}{V_2} \] If the final volume \( V_2 \) is not specified, you express \( P_2 \) in terms of \( V_2 \). --- ## d) Draw a P-V Diagram - The **P-V graph** for an isothermal process is a **hyperbola** (since \( PV = \text{constant} \)). - Mark **two points**: - (V₁, P₁) = (.4 m³, 100 kPa) - (V₂, P₂) **Sketch:** ``` | P | ● (V1,P1) r | . e | . s | . s | ● (V2, P2) u | (curve: PV = const) r | e +------------------------- V (Volume) ``` - The curve decreases as volume decreases and pressure increases for compression. --- ## **Summary Table** | State | P (kPa) | V (m³) | T (K) | |-------|---------|--------|----------| | 1 | 100 | .4 | 353.15 | | 2 | P₂ | V₂ | 353.15 | --- ## **Final Answers (in terms of V₂ or P₂):** ### **b) Work Done:** \[ \boxed{W = P_1 V_1 \ln\left(\frac{V_2}{V_1}\right) = 100 \times .4 \times \ln\left(\frac{V_2}{.4}\right)~\text{kJ}} \] ### **c) Final Pressure:** \[ \boxed{P_2 = \frac{P_1 V_1}{V_2} = \frac{100 \times .4}{V_2}~\text{kPa}} \] ### **d) P-V Diagram:** - Isothermal curve from (.4 m³, 100 kPa) to (V₂, P₂), as drawn above. --- **If you know the final volume (or pressure), you can substitute and get the numerical answers! If you have a specific final volume or pressure, let me know and I can plug in the numbers.**

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