Act like a helpful tutor and exlain me :
Give step-by-step solution with explanation and final answer:
What is the NACA
4
4
1
6
angle of attack where the wing operates at its highest efficiency or L
/
Dmax
.
AR
=
9
.
3
7
5
,
Oswald efficiency of
0
.
9
2
,
Zero
-
lift angle: about
–
4
°
.
Also don't consider drag do to air separation.
Question:
Act like a helpful tutor and exlain me :
Give step-by-step solution with explanation and final answer:
What is the NACA
4
4
1
6
angle of attack where the wing operates at its highest efficiency or L
/
Dmax
.
AR
=
9
.
3
7
5
,
Oswald efficiency of
0
.
9
2
,
Zero
-
lift angle: about
–
4
°
.
Also don't consider drag do to air separation.
This is AI generated Response.
Asked by: manish kumar
Created at: 2025-10-01 01:05:38
Final Answer:
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# Step-by-Step Solution: Angle of Attack for Maximum \( L/D \) of a NACA 4416 Airfoil
## Given Data
- **Airfoil:** NACA 4416
- **Aspect Ratio (\( AR \)):** \( 9.375 \)
- **Oswald Efficiency (\( e \)):** \( .92 \)
- **Zero-lift angle (\( \alpha_{L=} \)):** \( -4^\circ \)
- **No drag due to air separation** (assume only induced and profile drag)
## Step 1: Find the Lift and Drag Coefficients
### Lift Coefficient (\( C_L \))
For a cambered airfoil:
\[
C_L = a_ (\alpha - \alpha_{L=})
\]
Where:
- \( a_ \) = 2D lift slope (\( \approx 2\pi \) per radian for thin airfoils, NACA 4416 is close)
- \( \alpha \) = angle of attack (in radians)
- \( \alpha_{L=} \) = zero-lift angle (in radians)
### Drag Coefficient (\( C_D \))
The drag coefficient for a finite wing:
\[
C_D = C_{D,} + \frac{C_L^2}{\pi e AR}
\]
Where:
- \( C_{D,} \) = profile drag coefficient (parasitic drag, typically \( \approx .008 \) for NACA 4416)
- \( e \) = Oswald efficiency number
- \( AR \) = aspect ratio
## Step 2: Find Condition for Maximum \( L/D \)
\[
\frac{L}{D} = \frac{C_L}{C_D}
\]
To maximize \( L/D \), set the derivative of \( \frac{C_L}{C_D} \) with respect to \( C_L \) to zero, or recall that:
\[
\left( \frac{L}{D} \right)_{max} \text{ occurs when } C_{D,} = \frac{C_L^2}{\pi e AR}
\]
So,
\[
C_L = \sqrt{C_{D,} \cdot \pi e AR}
\]
## Step 3: Plug in the Numbers
Assume \( C_{D,} = .008 \) (typical for NACA 4416).
So,
\[
C_L = \sqrt{.008 \cdot \pi \cdot .92 \cdot 9.375}
\]
Calculate step by step:
1. \( \pi \cdot .92 = 2.890 \)
2. \( 2.890 \cdot 9.375 = 27.093 \)
3. \( .008 \cdot 27.093 = .2167 \)
4. \( \sqrt{.2167} \approx .465 \)
So,
\[
C_L \approx .465
\]
## Step 4: Find the Angle of Attack Corresponding to \( C_L \)
Recall:
\[
C_L = a_ (\alpha - \alpha_{L=})
\]
Where \( a_ = 2\pi \approx .11 \) per degree (since \( 2\pi \) per radian \( = .11 \) per degree).
So,
\[
.465 = .11 \cdot (\alpha - (-4))
\]
\[
.465 = .11 \cdot (\alpha + 4)
\]
\[
\alpha + 4 = \frac{.465}{.11} = 4.23
\]
\[
\alpha = 4.23 - 4 = .23^\circ
\]
## Step 5: Final Answer
### The angle of attack for maximum \( L/D \) is:
\[
\boxed{.2^\circ}
\]
## Summary Table
| Parameter | Value |
|----------------------|----------|
| \( AR \) | 9.375 |
| \( e \) | .92 |
| \( C_{D,} \) | .008 |
| \( C_L \) at \( L/D_{max} \) | .465 |
| \( \alpha_{L=} \) | \(-4^\circ\) |
| \( \alpha_{L/D_{max}} \) | \(.2^\circ\) |
---
**In words:**
The NACA 4416 wing at \( AR = 9.375 \), Oswald \( e = .92 \), and zero-lift angle of \(-4^\circ\), will have its maximum efficiency (\( L/D_{max} \)) at an angle of attack of about **\( .2^\circ \)**.
---
**Note:**
- This calculation assumes typical values for \( C_{D,} \). If you have a more precise value from wind tunnel data, use that.
- The result is sensitive to \( C_{D,} \) and the actual airfoil data.
- Angle is **relative to the chord line**.
---
**No image provided since the calculation is algebraic.**
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