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Act like a helpful tutor and exlain me : Give step-by-step solution with explanation and final answer:a i i & 4 I Bs oi

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Act like a helpful tutor and exlain me : Give step-by-step solution with explanation and final answer:Uploaded Imagea i i & 4 I Bs oi

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Asked by: 3quin0xx
Created at: 2025-09-29 19:12:37

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Let's break down the problem step by step: ## **Step 1: Understanding the Task** You need to: - Highlight **primary** (1°) alkyl carbons in **red**. - Highlight **secondary** (2°) alkyl carbons in **blue**. - Highlight **tertiary** (3°) alkyl carbons in **green**. ### **Definitions** - **Primary (1°) carbon:** Attached to **one** other carbon. - **Secondary (2°) carbon:** Attached to **two** other carbons. - **Tertiary (3°) carbon:** Attached to **three** other carbons. --- ## **Step 2: Analyzing the Structure** Let's number the carbons starting from the carbon bonded to the Cl (top wedge): 1. The carbon bonded to Cl. 2. The carbon bonded to Br (bottom wedge). 3. The carbon in the middle connecting 1 and 2. 4. The carbon in the ethyl group (left). 5. The terminal carbon of the ethyl group (leftmost). --- ## **Step 3: Classifying Each Carbon** - **Carbon 1 (Cl attached):** - Connected to: Cl, one carbon (central), one H. - **Primary** (1°). - **Carbon 2 (Br attached):** - Connected to: Br, one carbon (central), one H. - **Primary** (1°). - **Carbon 3 (central carbon):** - Connected to: Carbon 1, Carbon 2, Carbon 4, one H. - **Tertiary** (3°). - **Carbon 4 (ethyl group):** - Connected to: Carbon 3, Carbon 5, two H. - **Secondary** (2°). - **Carbon 5 (terminal ethyl):** - Connected to: Carbon 4, three H. - **Primary** (1°). --- ## **Step 4: Highlight Each Carbon** - **Red (Primary):** Carbons 1, 2, 5 - **Blue (Secondary):** Carbon 4 - **Green (Tertiary):** Carbon 3 --- ## **Step 5: Final Answer** **Here’s how you should highlight:** - **Red:** Carbon with Cl, Carbon with Br, and terminal carbon of ethyl group. - **Blue:** Carbon in the ethyl group attached to the central carbon. - **Green:** Central carbon attached to three other carbons. --- ### **Visual Summary** ``` Cl | C1 (red)---C3 (green)---C4 (blue)---C5 (red) | | Br (rest of molecule) | C2 (red) ``` - **C1:** Primary (red) - **C2:** Primary (red) - **C3:** Tertiary (green) - **C4:** Secondary (blue) - **C5:** Primary (red) --- **If you highlight as above, you'll have the correct classification!**

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