Act like a helpful tutor and exlain me :
Give step-by-step solution with explanation and final answer:5. Design a general purpose Go and No-Go plug gauge for inspecting a hole of 25D8, with the
following information: (i) i=0.45(D)/3 +0.001D in microns, (ii) The fundamental deviation for
hole D=16D 0.44, IT 8 = 25i, diameter 25 falls in step 18-30 mm.
Question:
Act like a helpful tutor and exlain me :
Give step-by-step solution with explanation and final answer:5. Design a general purpose Go and No-Go plug gauge for inspecting a hole of 25D8, with the
following information: (i) i=0.45(D)/3 +0.001D in microns, (ii) The fundamental deviation for
hole D=16D 0.44, IT 8 = 25i, diameter 25 falls in step 18-30 mm.
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Asked by: manish kumar
Created at: 2025-09-21 19:04:51
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Let's break down and solve the problem step by step.
---
## **Question Recap**
Design a **Go** and **No-Go plug gauge** for a **hole of 25D8** with:
- \( i = 0.45(D)^{1/3} + 0.001D \) in microns
- Fundamental deviation for hole: \( E_S = 16D^{0.44} \)
- IT8 = \( 25i \)
- D = 25 mm (since 25 falls in 18–30 mm step)
---
## **Step 1: Calculate the Standard Tolerance Unit, \( i \)**
Given:
- \( D = 25 \) mm
- \( i = 0.45(D)^{1/3} + 0.001D \) (in microns)
Calculate \( (25)^{1/3} \):
\[
25^{1/3} \approx 2.924
\]
Now,
\[
i = 0.45 \times 2.924 + 0.001 \times 25
\]
\[
i = 1.316 + 0.025
\]
\[
i = 1.341 \text{ microns}
\]
---
## **Step 2: Calculate IT8 Tolerance**
\[
IT8 = 25i = 25 \times 1.341 = 33.525 \text{ microns}
\]
---
## **Step 3: Fundamental Deviation (for D8 hole)**
For hole (D8), the fundamental deviation for holes is generally **zero** (for H holes) but for D holes, use:
\[
E_S = 16D^{0.44}
\]
Calculate \( D^{0.44} \):
\[
D^{0.44} = 25^{0.44}
\]
\[
\ln(25) = 3.21888
\]
\[
0.44 \times 3.21888 = 1.417
\]
\[
e^{1.417} \approx 4.13
\]
\[
E_S = 16 \times 4.13 \approx 66.08 \text{ microns}
\]
---
## **Step 4: Limits of Hole (D8)**
- **Lower Limit** = Basic Size + Fundamental Deviation = \( 25 + 66.08 \) microns = \( 25.06608 \) mm
- **Upper Limit** = Lower Limit + IT8 Tolerance = \( 25.06608 + 0.033525 \) mm = \( 25.099605 \) mm
---
## **Step 5: Go and No-Go Plug Gauge Design**
### **Go Gauge:**
- **Go Gauge** should enter the hole, so must be made to the lower limit (minimum size):
- **Go Plug Gauge size = Lower Limit = 25.066 mm**
### **No-Go Gauge:**
- **No-Go Gauge** should not enter if the hole is too large, i.e., made to the upper limit (maximum size):
- **No-Go Plug Gauge size = Upper Limit = 25.100 mm**
---
## **Step 6: Final Answers (rounded to suitable decimal places)**
- **Standard tolerance unit, \( i \) = 1.34 µm**
- **IT8 Tolerance = 33.53 µm**
- **Fundamental deviation (D8) = 66.08 µm**
- **Hole limits = 25.066 mm to 25.100 mm**
- **Go Plug Gauge size = 25.066 mm**
- **No-Go Plug Gauge size = 25.100 mm**
---
## **Summary Table**
| Parameter | Value |
|--------------------------|--------------|
| Standard unit (\(i\)) | 1.34 µm |
| IT8 Tolerance | 33.53 µm |
| Fundamental deviation | 66.08 µm |
| Hole Lower Limit | 25.066 mm |
| Hole Upper Limit | 25.100 mm |
| **Go Plug Gauge** | 25.066 mm |
| **No-Go Plug Gauge** | 25.100 mm |
---
### **Explanation**
- **Go gauge** ensures the hole is not smaller than the minimum acceptable size.
- **No-Go gauge** ensures the hole is not larger than the maximum acceptable size.
- Calculations follow ISO tolerance system for plug gauge design.
---
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