Sure! Let's break down the reaction step by step: --- ## **Step 1: Understanding the Reactants** The starting molecule is **1,2-dihydroxynaphthalene** (naphthalene ring with two adjacent OH groups). --- ## **Step 2: Understanding the Reagents** - **Na₂Cr₂O₇** (sodium dichromate) - **Acetone** - **H₂SO₄** (sulfuric acid) These reagents together are a **strong oxidizing system**. Sodium dichromate in acid is commonly used to oxidize alcohols. --- ## **Step 3: Predicting the Reaction** ### **What gets oxidized?** - The starting compound has **two neighboring hydroxyl (OH) groups** on an aromatic ring (1,2-dihydroxy). - With strong oxidizing agents, such as Na₂Cr₂O₇/H₂SO₄, **vicinal (neighboring) diols** on aromatic rings are oxidized to **quinones**. ### **What is the product?** - The two OH groups are oxidized to **carbonyl groups (=O)**. - This converts the molecule to **1,2-naphthoquinone**. --- ## **Step 4: Drawing the Product** - The product is naphthalene with **two ketone groups at positions 1 and 2** (next to each other). ### **Product Structure: 1,2-Naphthoquinone** ``` O O // \\ | | | | --- --- ``` Or, in words: The two OH groups are both replaced by C=O groups. --- ## **Summary Table** | Step | Structure Change | |----------------|--------------------------------| | Start | 1,2-dihydroxy-naphthalene | | Reagents | Na₂Cr₂O₇, H₂SO₄, acetone | | Product | 1,2-naphthoquinone | --- ## **Final Product** **1,2-naphthoquinone** If you need a drawn structure, just let me know!

## **Calculating Mass of Ethanol** To find the mass of ethanol given its volume and density, we can use the formula: \[ \text{Mass} = \text{Density} \times \text{Volume} \] ### **Given Data** - **Density of Ethanol**: \(0.789 \, \text{g/mL}\) - **Volume of Ethanol**: \(26.2 \, \text{mL}\) ### **Calculation** Substituting the values into the formula: \[ \text{Mass} = 0.789 \, \text{g/mL} \times 26.2 \, \text{mL} \] Calculating the mass: \[ \text{Mass} = 20.7068 \, \text{g} \] ### **Result** The mass of \(26.2 \, \text{mL}\) of ethanol is approximately **20.71 grams** (rounded to two decimal places).