Act like a helpful tutor and exlain me : Develop the formulas for the maximum radial and tangential stresses in a thick walled cylinder due to interbal pressure only
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Act like a helpful tutor and exlain me : Develop the formulas for the maximum radial and tangential stresses in a thick walled cylinder due to interbal pressure only
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Asked by: manish kumar
Created at: 2025-09-10 06:56:52
Asked by: manish kumar
Created at: 2025-09-10 06:56:52
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# Maximum Radial and Tangential Stresses in a Thick-Walled Cylinder (Internal Pressure Only)
## Problem Overview
A thick-walled cylinder (like a pressure vessel or pipe) is subjected to internal pressure \( p_i \). We want to derive formulas for:
- **Maximum radial stress** (\( \sigma_r \))
- **Maximum tangential (hoop) stress** (\( \sigma_\theta \))
Assume:
- Inner radius: \( r_i \)
- Outer radius: \( r_o \)
- Internal pressure: \( p_i \)
- External pressure: \( p_o = 0 \) (open to atmosphere)
---
## 1. **General Lame's Equations**
The general expressions for radial and tangential stresses at radius \( r \) are:
\[
\sigma_r(r) = A - \frac{B}{r^2}
\]
\[
\sigma_\theta(r) = A + \frac{B}{r^2}
\]
where \( A \) and \( B \) are constants found from boundary conditions.
---
## 2. **Boundary Conditions**
- At \( r = r_i \), \( \sigma_r(r_i) = -p_i \) (internal pressure, negative sign for compressive)
- At \( r = r_o \), \( \sigma_r(r_o) = 0 \) (open to air)
Substitute into the Lame's equation for \( \sigma_r \):
\[
\text{At } r_i: \quad -p_i = A - \frac{B}{r_i^2}
\]
\[
\text{At } r_o: \quad 0 = A - \frac{B}{r_o^2}
\]
---
## 3. **Solve for Constants \( A \) and \( B \)**
From the second boundary:
\[
A = \frac{B}{r_o^2}
\]
Plug into the first:
\[
-p_i = \frac{B}{r_o^2} - \frac{B}{r_i^2}
\]
\[
-p_i = B \left( \frac{1}{r_o^2} - \frac{1}{r_i^2} \right )
\]
\[
B = \frac{-p_i}{\frac{1}{r_o^2} - \frac{1}{r_i^2}} = \frac{-p_i r_o^2 r_i^2}{r_i^2 - r_o^2}
\]
Now \( A \):
\[
A = \frac{B}{r_o^2} = \frac{-p_i r_i^2}{r_i^2 - r_o^2}
\]
---
## 4. **Final Stress Formulas**
Plug back into general forms:
\[
\sigma_r(r) = \frac{-p_i r_i^2}{r_o^2 - r_i^2} \left( 1 - \frac{r_o^2}{r^2} \right)
\]
\[
\sigma_\theta(r) = \frac{-p_i r_i^2}{r_o^2 - r_i^2} \left( 1 + \frac{r_o^2}{r^2} \right)
\]
---
## 5. **Maximum Stresses**
### Maximum Radial Stress
- Occurs at \( r = r_i \):
\[
\sigma_{r, \max} = \sigma_r(r_i) = -p_i
\]
This is just the internal pressure (compressive).
### Maximum Tangential (Hoop) Stress
- Occurs at \( r = r_i \):
\[
\sigma_{\theta, \max} = \sigma_\theta(r_i) = \frac{-p_i r_i^2}{r_o^2 - r_i^2} \left( 1 + \frac{r_o^2}{r_i^2} \right)
\]
Simplify:
\[
1 + \frac{r_o^2}{r_i^2} = \frac{r_i^2 + r_o^2}{r_i^2}
\]
So,
\[
\sigma_{\theta, \max} = \frac{-p_i r_i^2}{r_o^2 - r_i^2} \cdot \frac{r_i^2 + r_o^2}{r_i^2}
= \frac{-p_i (r_i^2 + r_o^2)}{r_o^2 - r_i^2}
\]
Note: This is tensile (positive for \( p_i > 0 \), since denominator is negative, two negatives make positive).
---
## 6. **Summary Table**
| Location | Radial Stress (\( \sigma_r \)) | Tangential Stress (\( \sigma_\theta \)) |
|------------------|-------------------------------|-----------------------------------------|
| \( r = r_i \) | \( -p_i \) | \( \frac{p_i (r_i^2 + r_o^2)}{r_o^2 - r_i^2} \) |
| \( r = r_o \) | \( 0 \) | \( \frac{2 p_i r_i^2}{r_o^2 - r_i^2} \) |
---
## 7. **Key Points**
- **Maximum radial stress**: at inner wall, equal to \( -p_i \).
- **Maximum tangential (hoop) stress**: at inner wall, given by \( \frac{p_i (r_i^2 + r_o^2)}{r_o^2 - r_i^2} \).
---
## 8. **Diagram**

*Image: Thick-walled cylinder showing \( r_i \), \( r_o \), and internal pressure \( p_i \).*
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