Act like a helpful tutor and exlain me :dence interval conStUEEERTETET
7 suppose (FX) satisfy the 16050 squares assumptions in KY Concept 4
dom sample of size = 25015 drawn and yields
§=54422X. R= 026, SER = 62.
G1 09)
a. Tost Ho: pr = Ove HBr 7 0 at the 5% level
b. Construct 95% confidence jnterval for Bi
Suppose you learned that ¥iand were independent. Would YO! be
surprised? Explain.
———————
Bercises 203
4. Suppose Y;and X, are independent an
‘of the samples would Ho from (2) b oi i} ) mes Inwhitfmeton |
: o rejected? In what fraction of sample §
would the value §; = 0 bein i samples
[2 Included in the confidence interval from (0)? 1
ek vn By
Question:
Act like a helpful tutor and exlain me :dence interval conStUEEERTETET
7 suppose (FX) satisfy the 16050 squares assumptions in KY Concept 4
dom sample of size = 25015 drawn and yields
§=54422X. R= 026, SER = 62.
G1 09)
a. Tost Ho: pr = Ove HBr 7 0 at the 5% level
b. Construct 95% confidence jnterval for Bi
Suppose you learned that ¥iand were independent. Would YO! be
surprised? Explain.
———————
Bercises 203
4. Suppose Y;and X, are independent an
‘of the samples would Ho from (2) b oi i} ) mes Inwhitfmeton |
: o rejected? In what fraction of sample §
would the value §; = 0 bein i samples
[2 Included in the confidence interval from (0)? 1
ek vn By
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Asked by: Umesh
Created at: 2025-07-28 00:13:46
Final Answer:
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Absolutely! Let's break down the exercise step by step:
---
### Given Regression Output
A random sample of size \( n = 250 \) gives the regression:
\[
\hat{Y} = 5.4 + 3.2X, \quad R^2 = 0.26, \quad SER = 6.2
\]
(Standard errors in parentheses: \( (3.1) \) under 5.4, \( (1.5) \) under 3.2)
---
#### a. **Test \( H_0: \beta_1 = 0 \) vs. \( H_1: \beta_1 \neq 0 \) at the 5% level**
- **Null hypothesis (\(H_0\)):** The coefficient of \( X \) is zero (\( \beta_1 = 0 \))
- **Alternative hypothesis (\(H_1\)):** The coefficient of \( X \) is not zero (\( \beta_1 \neq 0 \))
**Test Statistic:**
\[
t = \frac{\text{Estimate} - \text{Null value}}{\text{Standard error}} = \frac{3.2 - 0}{1.5} \approx 2.13
\]
- With \( n = 250 \), the degrees of freedom are large, so the critical value for a 5% significance level (two-sided) is about 1.96.
**Decision:**
- \( |t| = 2.13 > 1.96 \), so we **reject \( H_0 \) at the 5% level**.
---
#### b. **Construct a 95% confidence interval for \( \beta_1 \)**
The formula is:
\[
\text{Estimate} \pm 1.96 \times \text{Standard error}
\]
\[
3.2 \pm 1.96 \times 1.5 = 3.2 \pm 2.94 = [0.26, 6.14]
\]
**So, the 95% confidence interval is:**
\[
[0.26, 6.14]
\]
---
#### c. **Suppose you learned that \( Y_i \) and \( X_i \) were independent. Would you be surprised? Explain.**
- If \( Y \) and \( X \) are independent, the true value of \( \beta_1 \) should be **zero** (because changes in \( X \) don't affect \( Y \)).
- However, our confidence interval **does not include zero**, and we rejected \( H_0 \) at 5%. This suggests there **is** a relationship in the data.
- **Conclusion:** Yes, you should be surprised, because the data suggests a statistically significant relationship, but independence would mean there should be none.
---
#### d. **(Theoretical) If \( Y_i \) and \( X_i \) are independent and many samples of size \( n = 250 \) are drawn...**
1. **Fraction of samples in which \( H_0 \) is rejected:**
- If \( H_0 \) is true, the **Type I error rate** is the significance level: **5%** of samples would (incorrectly) reject \( H_0 \).
2. **Fraction of samples in which \( \beta_1 = 0 \) is included in the 95% confidence interval:**
- By construction, **95%** of the confidence intervals would contain the true value (\( \beta_1 = 0 \)).
---
### Summary Table
| Part | Concept | Key Steps/Answers |
|------|---------|------------------|
| (a) | t-test | t = 2.13, reject \( H_0 \) |
| (b) | CI | [0.26, 6.14] |
| (c) | Independence | Surprised, since the data suggests a relation |
| (d) | Repeated Sampling | 5% reject \( H_0 \); 95% include 0 in CI |
Let me know if you want more details on any part!
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