VIPSolutionsAct like a helpful tutor and exlain me :55. Give suc a hrm ec ich cb ed 1 cry ot de Prrmsn ds on. pon) 26. Gives TUPAC name oe comprd sma tlm. (1 i) 27 Give tesco te ma crane prot hich es ben cope mcyrpes 1] Aka yopy chy ropa peed wi FCC. 1 rc ca se snd opin. (pom) 1. How many acy bydogen sos coiod in he componmd 3d 15h [43 meen 15 del? (1 pom)
Question:
Act like a helpful tutor and exlain me :
55. Give suc a hrm ec ich cb ed 1 cry ot de Prrmsn ds
on. pon)
26. Gives TUPAC name oe comprd sma tlm. (1 i)
27 Give tesco te ma crane prot hich es ben cope mcyrpes 1]
Aka yopy chy ropa peed wi FCC. 1 rc ca se
snd opin. (pom)
1. How many acy bydogen sos coiod in he componmd 3d 15h
[43 meen 15 del? (1 pom)
This is AI generated Response.
Asked by: Alok Kumar
Created at: 2026-01-27 06:28:12
Asked by: Alok Kumar
Created at: 2026-01-27 06:28:12
Final Answer:
Rendered
Raw Text
Did you like this answer?
Absolutely! Let's break down each question step by step.
---
## **Question 25**
**Give a sequence of laboratory reactions to carry out the transformation below:**
- **Starting Material:** Benzene (C₆H₆)
- **Product:** 1-Phenyl-1-heptanone (C₆H₅CO(CH₂)₅CH₃)
### **Step-by-Step Solution:**
1. **Friedel-Crafts Acylation:**
- React benzene with heptanoyl chloride (C₆H₁₃COCl) and AlCl₃.
- This forms 1-phenyl-1-heptanone.
- **Equation:**
C₆H₆ + C₆H₁₃COCl + AlCl₃ → C₆H₅CO(CH₂)₅CH₃
**Sequence:**
1. Prepare heptanoyl chloride from heptanoic acid (if needed):
Heptanoic acid + SOCl₂ → Heptanoyl chloride
2. Friedel-Crafts acylation:
Benzene + Heptanoyl chloride + AlCl₃ → 1-Phenyl-1-heptanone
---
## **Question 26**
**Give an IUPAC name for the compound shown below:**
- Structure:
```
|
CH3-CH2-CH-CH2-CH-CH3
| |
CH3 CH3
```
### **Step-by-Step Solution:**
1. **Identify the longest chain:** 6 carbons (hexane).
2. **Number the chain from the end nearest a substituent:**
- Methyl on C-3 and C-5.
3. **Name:** 3,5-Dimethylhexane
---
## **Question 27**
**Give the structure for the major organic product when 1-cyclopentyl-2-methylpropan-2-ol is treated with PCC. If no reaction, explain why.**
- **PCC (Pyridinium chlorochromate):** Oxidizes primary and secondary alcohols.
### **Step-by-Step Solution:**
- The alcohol is on a tertiary carbon (2-methylpropan-2-ol group), which cannot be oxidized by PCC (PCC does **not** oxidize tertiary alcohols).
- **Answer:**
**No reaction** occurs because PCC does not oxidize tertiary alcohols (no hydrogen on the carbon bearing the OH group).
---
## **Question 28**
**How many acetylenic hydrogen atoms are in 3,4-dimethyl-1,5-hexadiyne?**
- **Structure:**
CH₃C≡C-CH(CH₃)-C≡C-CH₃
### **Step-by-Step Solution:**
- Acetylenic hydrogens are hydrogens directly attached to a carbon of a triple bond.
- Here, both triple bonds are internal (no terminal alkynes), so **zero** acetylenic hydrogens are present.
---
### **Summary Table**
| Q# | Key Point |
|----|-----------|
| 25 | Friedel–Crafts acylation (Benzene + Heptanoyl chloride + AlCl₃) |
| 26 | 3,5-Dimethylhexane |
| 27 | No reaction (PCC does not oxidize tertiary alcohols) |
| 28 | acetylenic hydrogens |
---
Ask if you want more details or explanations on any question!
📢 Instructions:
- Ask anything relatd to above question only.
- For new Question goto :