Absolutely, let me help you understand how to **complete this table for H₂O** (water/steam) using thermodynamic tables. --- ## **Step-by-Step Explanation** ### **1. Understanding the Table** The columns are: - **T, °F:** Temperature in degrees Fahrenheit. - **P, psia:** Pressure in pounds per square inch absolute. - **u, Btu/lbm:** Specific internal energy in British Thermal Units per pound mass. - **Phase description:** Whether the state is subcooled liquid, saturated mixture, or superheated vapor. --- ### **2. How to Fill the Table** For each row, you must find the missing values using **steam tables** (thermodynamic property tables for water/steam). #### **A. When T and u are given:** - Use the given **u** at the specified **T** to find the corresponding **phase** and **P**. #### **B. When T and P are given:** - Look up the properties at that T and P in the superheated steam tables or saturated tables. - Find **u** and the phase (subcooled, saturated, or superheated). --- ### **3. Example Solutions** Let’s analyze each row: --- #### **Row 1:** `T = 300°F, u = 782 Btu/lbm` - Look up the **steam tables** at T = 300°F. - Find the **saturated vapor internal energy** (u_g) at 300°F. - In the saturated steam tables: - At 300°F, u_g ≈ **782 Btu/lbm** - Since u matches u_g, the phase is **saturated vapor**. - The **saturation pressure** at 300°F is **67.02 psia** (from steam tables). **Row 1 Completed:** | T (°F) | P (psia) | u (Btu/lbm) | Phase description | |--------|----------|-------------|--------------------| | 300 | 67.02 | 782 | Saturated vapor | --- #### **Row 2:** `T = 500°F, P = 40 psia` - At T = 500°F and P = 40 psia, check if this is superheated steam: - The **saturation temperature** at 40 psia is about **267°F**. - Since 500°F > 267°F, it’s **superheated vapor**. - Look up the **superheated steam tables** for T = 500°F, P = 40 psia: - u ≈ **1220 Btu/lbm** (can vary slightly by table). **Row 2 Completed:** | T (°F) | P (psia) | u (Btu/lbm) | Phase description | |--------|----------|-------------|--------------------| | 500 | 40 | 1220 | Superheated vapor | --- #### **Row 3:** `T = 400°F, P = 120 psia` - The **saturation temperature** at 120 psia is about **350°F**. - Since 400°F > 350°F, it's **superheated vapor**. - From the superheated steam tables at T = 400°F, P = 120 psia: - u ≈ **1130 Btu/lbm** **Row 3 Completed:** | T (°F) | P (psia) | u (Btu/lbm) | Phase description | |--------|----------|-------------|--------------------| | 400 | 120 | 1130 | Superheated vapor | --- #### **Row 4:** `T = 400°F, P = 400 psia` - The **saturation temperature** at 400 psia is about **445°F**. - Since 400°F < 445°F, it’s a **compressed liquid (subcooled liquid)**. - Use compressed liquid tables or approximate with saturated liquid at 400°F: - u_f at 400°F ≈ **368 Btu/lbm** **Row 4 Completed:** | T (°F) | P (psia) | u (Btu/lbm) | Phase description | |--------|----------|-------------|--------------------| | 400 | 400 | 368 | Compressed liquid | --- ## **Summary Table** | T (°F) | P (psia) | u (Btu/lbm) | Phase description | |--------|----------|-------------|--------------------| | 300 | 67.02 | 782 | Saturated vapor | | 500 | 40 | 1220 | Superheated vapor | | 400 | 120 | 1130 | Superheated vapor | | 400 | 400 | 368 | Compressed liquid | --- ## **How to Use Steam Tables** 1. **Identify the state:** Compare T and P with saturation values. 2. **Find u:** Use the correct table (saturated or superheated). 3. **Describe the phase:** Based on T and P. Let me know if you want to see how to look up values in the tables or if you need help with a specific row!