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A. The hour angle (HA) is the difference between the local sidereal time (LST) and the right ascension (RA) of the star, given by HA = LST - RA. At transit, HA = 0. Since Rigel will transit in 75 minutes (1.25 hours), it is currently east of the meridian, so its HA is negative. Thus, the HA is -1.25. B. LST = RA - 1.25 hours = 05h 14m 32.3s - 1h 15m = 03h 59m 32.3s. C. A star due east on the horizon must have a declination of approximately 0° (on the celestial equator) to rise exactly due east. Such a star has HA = -6 hours, so its RA = LST - HA = LST + 6 hours = 03h 59m 32.3s + 6h = 09h 59m 32.3s. D. Rigel will set when its HA is approximately +6 hours (since its declination is close to 0°, similar to an equatorial star, which sets 6 sidereal hours after transit). Thus, LST at setting ≈ RA + 6 hours = 05h 14m 32.3s + 6h = 11h 14m 32.3s.

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A. The hour angle (HA) is the difference between the local sidereal time (LST) and the right ascension (RA) of the star, given by HA = LST - RA. At transit, HA = 0. Since Rigel will transit in 75 minutes (1.25 hours), it is currently east of the meridian, so its HA is negative. Thus, the HA is -1.25. B. LST = RA - 1.25 hours = 05h 14m 32.3s - 1h 15m = 03h 59m 32.3s. C. A star due east on the horizon must have a declination of approximately 0° (on the celestial equator) to rise exactly due east. Such a star has HA = -6 hours, so its RA = LST - HA = LST + 6 hours = 03h 59m 32.3s + 6h = 09h 59m 32.3s. D. Rigel will set when its HA is approximately +6 hours (since its declination is close to 0°, similar to an equatorial star, which sets 6 sidereal hours after transit). Thus, LST at setting ≈ RA + 6 hours = 05h 14m 32.3s + 6h = 11h 14m 32.3s.

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Asked by: vishal
Created at: 2025-09-11 03:25:25

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# Astronomy Problem Solutions ## A. Hour Angle (HA) of Rigel - **Formula:** \[ \text{HA} = \text{LST} - \text{RA} \] - **At transit:** HA = 0. - **Time until transit:** 75 minutes = 1.25 hours. - **Current position:** Rigel is east of the meridian, so HA is negative. - **Result:** \[ \boxed{\text{HA} = -1.25~\text{hours}} \] --- ## B. Local Sidereal Time (LST) Now - **Given:** - \(\text{RA}_\text{Rigel} = 05^{\mathrm{h}}\,14^{\mathrm{m}}\,32.3^{\mathrm{s}}\) - \(\text{HA} = -1.25~\text{hours}\) - **Formula:** \[ \text{LST} = \text{RA} + \text{HA} \] - **Calculation:** \[ \text{LST} = 05^{\mathrm{h}}\,14^{\mathrm{m}}\,32.3^{\mathrm{s}} + (-1^{\mathrm{h}}\,15^{\mathrm{m}}) \] \[ = 03^{\mathrm{h}}\,59^{\mathrm{m}}\,32.3^{\mathrm{s}} \] - **Result:** \[ \boxed{\text{LST} = 03^{\mathrm{h}}\,59^{\mathrm{m}}\,32.3^{\mathrm{s}}} \] --- ## C. RA of a Star Rising Due East - **Condition:** Star due east means it is on the horizon at azimuth \(90^\circ\). - **For an observer at mid-latitude:** - A star rises due east if declination \(\delta \approx 0^\circ\) (celestial equator). - Such a star rises when HA = \(-6~\text{hours}\). - **Formula:** \[ \text{RA} = \text{LST} - \text{HA} = \text{LST} + 6~\text{hours} \] - **Calculation:** \[ \text{RA}_\text{east} = 03^{\mathrm{h}}\,59^{\mathrm{m}}\,32.3^{\mathrm{s}} + 06^{\mathrm{h}} = 09^{\mathrm{h}}\,59^{\mathrm{m}}\,32.3^{\mathrm{s}} \] - **Result:** \[ \boxed{\text{RA}_\text{east} = 09^{\mathrm{h}}\,59^{\mathrm{m}}\,32.3^{\mathrm{s}}} \] --- ## D. LST When Rigel Sets - **Setting condition:** For a star near the celestial equator, it sets when HA = \(+6~\text{hours}\). - **Formula:** \[ \text{LST}_{\text{set}} = \text{RA} + 6~\text{hours} \] - **Calculation:** \[ \text{LST}_{\text{set}} = 05^{\mathrm{h}}\,14^{\mathrm{m}}\,32.3^{\mathrm{s}} + 06^{\mathrm{h}} = 11^{\mathrm{h}}\,14^{\mathrm{m}}\,32.3^{\mathrm{s}} \] - **Result:** \[ \boxed{\text{LST}_{\text{set}} = 11^{\mathrm{h}}\,14^{\mathrm{m}}\,32.3^{\mathrm{s}}} \] --- ## Summary Table | Part | Question | Answer | |------|--------------------------------------------------------|------------------------------| | A | Current hour angle of Rigel | \(-1.25~\text{hours}\) | | B | Current LST | \(03^{\mathrm{h}}\,59^{\mathrm{m}}\,32.3^{\mathrm{s}}\) | | C | RA of a star rising due east | \(09^{\mathrm{h}}\,59^{\mathrm{m}}\,32.3^{\mathrm{s}}\) | | D | LST when Rigel sets | \(11^{\mathrm{h}}\,14^{\mathrm{m}}\,32.3^{\mathrm{s}}\) |

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