A machine tool receives an input power of 1 2 kW . If mechanical losses are 1 8 % , calculate the useful output power.explain in detail
Question:
A machine tool receives an input power of 1 2 kW . If mechanical losses are 1 8 % , calculate the useful output power.explain in detail
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Asked by: manish kumar
Created at: 2025-12-16 08:59:00
Asked by: manish kumar
Created at: 2025-12-16 08:59:00
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# Calculation of Useful Output Power
Given:
- **Input power** (\( P_{in} \)) = 12 kW
- **Mechanical losses** = 18%
## Step 1: Calculate Mechanical Losses (in kW)
Mechanical losses represent the portion of input power lost due to friction, heat, etc., and not available as useful output.
\[
\text{Mechanical losses} = \frac{18}{100} \times 12 \text{ kW}
\]
\[
= .18 \times 12 \text{ kW}
\]
\[
= 2.16 \text{ kW}
\]
## Step 2: Calculate Useful Output Power
Useful output power is the remaining power after deducting losses from the input.
\[
\text{Useful output power} = \text{Input power} - \text{Mechanical losses}
\]
\[
= 12 \text{ kW} - 2.16 \text{ kW}
\]
\[
= 9.84 \text{ kW}
\]
## Step 3: Final Answer
**The useful output power of the machine tool is:**
\[
\boxed{9.84\ \text{kW}}
\]
---
**Summary Table:**
| Quantity | Value |
|-----------------------|------------|
| Input Power (\(P_{in}\)) | 12 kW |
| Mechanical Losses | 2.16 kW |
| Useful Output Power | 9.84 kW |
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