# Gas Absorption Tower Efficiency Calculation ## Problem Restatement - **Feed solute rate:** \(90 \text{ kmol/h}\) - **Amount of solute removed:** \(72 \text{ kmol/h}\) We are to calculate the **absorption efficiency** of the tower. --- ## Step 1: Understanding Absorption Efficiency **Absorption efficiency** is defined as the percentage of solute removed from the feed relative to the total solute entering: \[ \text{Absorption Efficiency (\%)} = \left( \frac{\text{Amount of solute removed}}{\text{Amount of solute in feed}} \right) \times 100 \] --- ## Step 2: Substitute Values Given: - Amount of solute removed = \(72 \text{ kmol/h}\) - Amount of solute in feed = \(90 \text{ kmol/h}\) \[ \text{Absorption Efficiency (\%)} = \left( \frac{72}{90} \right) \times 100 \] --- ## Step 3: Calculate \[ \frac{72}{90} = .8 \] \[ .8 \times 100 = 80 \] --- ## Final Answer \[ \boxed{80\%} \] **The absorption efficiency of the tower is 80%.**