# Gas Absorption Tower Efficiency Calculation ## Problem Statement - **Solute in feed:** 90 kmol/hr - **Solute removed:** 72 kmol/hr **Calculate the absorption efficiency of the tower.** --- ## Step 1: Understanding Absorption Efficiency **Absorption Efficiency** is defined as the fraction (or percentage) of solute removed from the feed by the tower: \[ \text{Absorption Efficiency} = \frac{\text{Amount of solute removed}}{\text{Amount of solute in feed}} \times 100\% \] --- ## Step 2: Substitute Values Given: - Amount removed = \(72 \text{ kmol/hr}\) - Amount in feed = \(90 \text{ kmol/hr}\) \[ \text{Absorption Efficiency} = \frac{72}{90} \times 100\% \] --- ## Step 3: Calculate \[ \frac{72}{90} = .8 \] \[ .8 \times 100\% = 80\% \] --- ## Final Answer **The absorption efficiency of the tower is \( \boxed{80\%} \).**