Let's analyze the given problem: ### Shear Force Diagram (Top Image): - Starts at **+10 kN** at the left end. - Decreases linearly to **0 kN** at 5 m. - Continues to decrease linearly to **-4 kN** at 8 m. ### Loading Diagram Analysis: - **A linear change in the shear force diagram** indicates a **uniformly distributed load (UDL)** on the beam. - **A sudden jump in the shear force** would indicate a point load (which we do not see here). ### Matching with Options: Looking at the three loading diagram options: #### First Option: - 10 kN point load at A, followed by a UDL of 2 kN/m. This would result in a sudden drop (jump) in the shear force diagram, which we do **not** see in the provided SFD. #### Second Option: - Only a UDL of 2 kN/m over the length AB. The shear force should **start at a value and decrease linearly**, but the starting value should match the area under the load up to that point. #### Third Option: - A UDL of 2 kN/m and a moment at A. The moment would affect the **bending moment diagram**, but not the shear force diagram directly. ### Calculating the Shear at Each Point: If we only have a UDL: - Shear at left end = Reaction at A. - Shear decreases linearly due to the UDL. Given that the shear force starts at +10 kN and ends at -4 kN after 8 m: - Change in shear = -4 - 10 = -14 kN over 8 m. - UDL = Change in shear / Length = 14/8 = 1.75 kN/m (very close to 2 kN/m, possibly rounded). ### **Conclusion:** The **second option** (middle diagram) is most consistent with the given shear force diagram, as it represents a UDL of 2 kN/m over the entire span, which matches the linear decrease in the shear force diagram. --- **Final Answer:** **The correct loading diagram for the given shear force diagram is the second (middle) option.**