Let's carefully analyze the question: **Question:** A slab is rotating about a fixed axis passing through point G which is also its center of mass. Calculate the linear momentum about point P on the slab. --- ### **Step-by-Step Solution:** #### **Key Points:** - The slab rotates about point G (the center of mass). - Linear momentum (**not angular momentum**) is being asked about point P. #### **Concept:** - For a rigid body rotating about its center of mass (G), **the center of mass does not move** (its velocity is zero). - Thus, the **total linear momentum of the body is zero** (since the velocity of the center of mass is zero). #### **Answer:** \[ \boxed{0 \text{ kg·m/s}} \] **Explanation:** Linear momentum is a property that depends on the movement of the center of mass. If the center of mass is not moving (as it is the axis of rotation), the total linear momentum is zero, regardless of the rotational motion about this point. --- **So, the correct option is:** - 0 kg·m/s