The question shown in the image is: "Consider a rectangular tank which is 6 m long, 4 m wide, and 2 m high is floating in a fluid of density ρ. The rectangular tank is placed such that the length 6 m length is held vertically and the depth of immersion of the rectangular tank is 4/3 m. The rectangular tank is in ______ equilibrium." ### Answer Explanation: The equilibrium of a floating body depends on the relative positions of the center of gravity (G) and the metacenter (M): - **Stable equilibrium:** M is above G. - **Unstable equilibrium:** M is below G. - **Neutral equilibrium:** M coincides with G. Given: - Length (vertical) = 6 m - Width = 4 m - Height = 2 m - Depth of immersion = 4/3 m For a floating body to be in stable equilibrium, its metacentric height (GM) must be positive (i.e., M above G). For such a tall and narrow orientation (6 m vertical), the metacentric height is likely to be negative, making the equilibrium **unstable**. ### **Correct Answer:** > **Unstable** This is because a tall, narrow floating object tends to tip over easily, indicating unstable equilibrium.