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**Step 3: Step-by-Step Calculation** **Detailed Explanation:** 1. **Support Reactions:** - The truss has a pin support at **A** and a roller support at **E**. - A vertical load of **100 kN** is applied at point **J**. Using moments about **A** to find the reaction at **E**: \[ \sum M_A = 0 \] - The load at **J** causes a moment about **A**: \[ E_y \times 8\, \text{m} - 100\, \text{kN} \times 8\, \text{m} = 0 \] \[ E_y = \frac{100 \times 8}{8} = 100\, \text{kN} \] - Vertical equilibrium: \[ A_y + E_y = 100\, \text{kN} \] \[ A_y + 100 = 100 \] \[ A_y = 0 \] 2. **Cutting the Truss:** - Cut through members **CF**, **BC**, and **FG**. - The cut divides the truss into two parts; analyze the **left section**. 3. **Analyzing the Left Section:** - Known: - Support reactions: \(A_y = 0\), \(E_y = 100\, \text{kN}\) - Member forces to find: **CF**, **BC**, **FG** - Assign coordinates: - F at (2,0) - C at (4,1) - B at (2,1) - G at (4,0) write the explanation in text in 4 to lines

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**Step 3: Step-by-Step Calculation** **Detailed Explanation:** 1. **Support Reactions:** - The truss has a pin support at **A** and a roller support at **E**. - A vertical load of **100 kN** is applied at point **J**. Using moments about **A** to find the reaction at **E**: \[ \sum M_A = 0 \] - The load at **J** causes a moment about **A**: \[ E_y \times 8\, \text{m} - 100\, \text{kN} \times 8\, \text{m} = 0 \] \[ E_y = \frac{100 \times 8}{8} = 100\, \text{kN} \] - Vertical equilibrium: \[ A_y + E_y = 100\, \text{kN} \] \[ A_y + 100 = 100 \] \[ A_y = 0 \] 2. **Cutting the Truss:** - Cut through members **CF**, **BC**, and **FG**. - The cut divides the truss into two parts; analyze the **left section**. 3. **Analyzing the Left Section:** - Known: - Support reactions: \(A_y = 0\), \(E_y = 100\, \text{kN}\) - Member forces to find: **CF**, **BC**, **FG** - Assign coordinates: - F at (2,0) - C at (4,1) - B at (2,1) - G at (4,0) write the explanation in text in 4 to lines

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Asked by: Kumar
Created at: 2025-07-27 15:10:04

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First, determine the reactions: the roller at E carries the entire 100 kN load applied at J, so \(E_y = 100\,\text{kN}\), and the pin at A carries no vertical force (\(A_y = 0\)). Next, cut through members CF, BC, and FG and analyze the left section of the truss using equilibrium equations to solve for the forces in these members, assigning coordinates to key joints for geometry reference. The internal forces are then found by applying \(\sum M\), \(\sum F_x\), and \(\sum F_y\) to the isolated section.

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