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Asked by: Test User 100261
Created at: 2025-05-13 14:48:42
Final Answer:
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The image provides a **step-by-step solution** for deriving the velocity profile of a Casson fluid flowing inside a tube. Here is a summary of the key points and equations presented:
---
### **Approach and Relevant Equations**
- **Casson Fluid Constitutive Equation:**
\[
\sigma_{\tau} = 2\mu \left(\mathbf{D}\right)^{\frac{1}{2}} + \tau_0
\]
where:
- \(\sigma_{\tau}\) = shear stress
- \(\mu\) = viscosity
- \(\mathbf{D}\) = shear rate
- \(\tau_0\) = yield stress
---
### **Step-by-Step Solution**
#### **1. Force Balance**
- Consider a differential element of fluid inside the tube.
- Two forces act on the element:
1. **Shear Force** (acts tangentially to the wall)
2. **Pressure Force** (from the pressure gradient along the tube)
- **Force Balance Equation:**
\[
\frac{d\sigma_{\tau}}{dx} = \frac{d}{dx}\left[2\mu \left(\frac{dv}{dy}\right)^{\frac{1}{2}} + \tau_0\right]
\]
#### **2. Shear Stress and Velocity Gradient**
- Shear stress relates to the velocity gradient (\(\frac{dv}{dy}\)), i.e.,
\[
\sigma_{\tau} = 2\mu \left(\frac{dv}{dy}\right)^{\frac{1}{2}} + \tau_0
\]
- Substitute into the force balance to get a differential equation for velocity profile.
---
### **Solution for Velocity Profile**
- After integration and applying boundary conditions (such as the no-slip condition at the wall), you derive the **velocity profile for Casson fluid**.
- The final solution contains terms with both yield stress (\(\tau_0\)) and viscosity (\(\mu\)).
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### **Explanation**
- The velocity profile is derived by:
- Starting with the constitutive equation for Casson fluid
- Applying force balance to get a differential equation
- Solving the equation with appropriate boundary conditions
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If you need the explicit integrated velocity profile or further steps for a specific geometry (like a cylindrical tube), let me know!
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