rs ae . ~~ Thegiven circuit translates to which at fF = BE = y ” b Ee c “
Question:
rs ae .
~~ Thegiven circuit translates to which at
fF = BE
=
y ”
b Ee
c “
This is AI generated Response.
Asked by: Test User 100047
Created at: 2025-05-08 02:21:53
Asked by: Test User 100047
Created at: 2025-05-08 02:21:53
Final Answer:
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Let's break down the circuit step by step:
1. The top input is **a** going through a NOT gate, so that becomes **¬a** (or a').
2. The second input is **b** going through a NOT gate, so that becomes **¬b** (or b').
3. The output of the NOT gate for **b** and the input **c** go into an AND gate, so that becomes **(¬b AND c)** (or b'c).
4. The outputs of the NOT gate for **a** and the AND gate (from step 3) go into an OR gate, so the final output is:
**y = (¬a) OR (¬b AND c)**
Or in Boolean algebra:
**y = a' + b'c**
So, the equation is:
\[
\boxed{y = a' + b'c}
\]
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