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Uploaded Imager— st =e nan asd a.

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Asked by: Seden
Created at: 2025-09-21 03:07:21

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Let's break down the problem step by step using the table data: ### Table Data | | A | B | C | D | |---------------------|-----|-----|-----|-----| | Order Accurate | 320 | 270 | 233 | 137 | | Order Not Accurate | 18 | 20 | 19 | 9 | ### Question Find the **probability of getting an order from Restaurant C or an order that is not accurate**. #### Step 1: Find the total number of orders Total orders = Sum of all entries in the table \[ \text{Total orders} = (320 + 270 + 233 + 137) + (18 + 20 + 19 + 9) \] \[ = 960 + 66 = 1026 \] #### Step 2: Find the number of orders from Restaurant C Total from C = Accurate from C + Not Accurate from C \[ = 233 + 19 = 252 \] #### Step 3: Find the number of orders that are not accurate Total not accurate = 18 + 20 + 19 + 9 = 66 #### Step 4: Find overlap (orders from C that are not accurate) Orders from C that are not accurate = 19 #### Step 5: Use the formula for probability of A or B: \[ P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B) \] Here, - \(A = \) order from Restaurant C (252 orders) - \(B = \) order that is not accurate (66 orders) - \(A \cap B = \) order from C that is not accurate (19 orders) So, \[ P(\text{C or Not Accurate}) = \frac{252}{1026} + \frac{66}{1026} - \frac{19}{1026} \] \[ = \frac{252 + 66 - 19}{1026} \] \[ = \frac{299}{1026} \] \[ \approx 0.291 \] ### **Final Answer** **The probability of getting an order from Restaurant C or an order that is not accurate is:** \[ \boxed{0.291} \] (Rounded to three decimal places)

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