min Ql median Qs max mean sd n missing
0.0688 0.133 0.1514 0.1697 0.2706 0.1518 0.0244 10000 0
Learn by Doing
Using correct values, calculate and report the lower and upper bounds of the 95% confidence interval for the proportion of all
OSU faculty, staff, and students wearing orange on Fridays during football season. Report both bounds to FOUR decimal
or
Question:
min Ql median Qs max mean sd n missing
0.0688 0.133 0.1514 0.1697 0.2706 0.1518 0.0244 10000 0
Learn by Doing
Using correct values, calculate and report the lower and upper bounds of the 95% confidence interval for the proportion of all
OSU faculty, staff, and students wearing orange on Fridays during football season. Report both bounds to FOUR decimal
or
This is AI generated Response.
Asked by: Umesh
Created at: 2025-07-26 10:45:10
Final Answer:
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Let's break down the calculation for the 95% confidence interval for a proportion, given the summary statistics:
- **mean (p̂):** 0.1518
- **sd:** 0.0244
- **n:** 10,000
### Step 1: Formula for Confidence Interval
For a proportion, the 95% confidence interval is:
\[
\text{CI} = \hat{p} \pm z^* \times \frac{sd}{\sqrt{n}}
\]
But since the mean and sd are provided from the sample, and n is large, we can use:
\[
\text{CI} = \hat{p} \pm z^* \times sd
\]
For 95% confidence, \( z^* = 1.96 \).
### Step 2: Plug in the Values
\[
\text{Lower bound} = 0.1518 - 1.96 \times 0.0244
\]
\[
\text{Upper bound} = 0.1518 + 1.96 \times 0.0244
\]
### Step 3: Calculation
- \( 1.96 \times 0.0244 = 0.047824 \)
So,
- **Lower bound:** \( 0.1518 - 0.047824 = 0.103976 \)
- **Upper bound:** \( 0.1518 + 0.047824 = 0.199624 \)
### Step 4: Round to Four Decimal Places
- **Lower bound:** 0.1040
- **Upper bound:** 0.1996
---
**Final Answer:**
\[
\boxed{0.1040,\ 0.1996}
\]
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