Let's calculate the 95% confidence interval for the mean proportion. Given data: - Mean (\(\bar{x}\)) = **0.1518** - Standard deviation (sd) = **0.0244** - Sample size (n) = **10,000** The formula for the 95% confidence interval for the mean proportion is: \[ \bar{x} \pm z \times \frac{sd}{\sqrt{n}} \] For a 95% confidence interval, **z = 1.96**. Let's plug in the values: 1. **Standard Error (SE):** \[ SE = \frac{0.0244}{\sqrt{10000}} = \frac{0.0244}{100} = 0.000244 \] 2. **Margin of Error:** \[ ME = 1.96 \times 0.000244 = 0.00047824 \] 3. **Lower bound:** \[ 0.1518 - 0.00047824 = 0.1513 \] 4. **Upper bound:** \[ 0.1518 + 0.00047824 = 0.1523 \] **Final Answers (to four decimal places):** - **Lower bound:** 0.1513 - **Upper bound:** 0.1523 **Fill in the blanks:** ( **0.1513** , **0.1523** )