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lg ——— UTi rent ation has the ooing al me {i a ] i RT ee ne Ee following bifurcation diagrab] — Co ea b SRR I i | rn Hs | HL { 4 5 ire He J 1 hd | Py a Ee ia ge = LL rl E i P WE 7 LEH = a ] ; = — gE : A SEE = rE — a ——= Fr Ea = Lh ses a. Fg — | —= LL : a Li i; Lo = 1 Pia ; ——— = | i — = ym : FE (ll LE suomi Question a | — 1 | ma a = iE = HE : EE = i ; a Sea : = a = co Ee i J ha a Te = PE ? a Ee ee

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Uploaded Imagelg ——— UTi rent ation has the ooing al me {i a ] i RT ee ne Ee following bifurcation diagrab] — Co ea b SRR I i | rn Hs | HL { 4 5 ire He J 1 hd | Py a Ee ia ge = LL rl E i P WE 7 LEH = a ] ; = — gE : A SEE = rE — a ——= Fr Ea = Lh ses a. Fg — | —= LL : a Li i; Lo = 1 Pia ; ——— = | i — = ym : FE (ll LE suomi Question a | — 1 | ma a = iE = HE : EE = i ; a Sea : = a = co Ee i J ha a Te = PE ? a Ee ee

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Asked by: SANJAY
Created at: 2025-10-15 05:59:50

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# Identifying the Differential Equation from the Bifurcation Diagram The diagram shown in your image is a classical **saddle-node (or fold) bifurcation**. This is indicated by the way two fixed points (one stable, one unstable) appear as the parameter \( a \) increases, and then disappear for lower values of \( a \). ## Standard Form The standard differential equation for a saddle-node bifurcation is: \[ \frac{dy}{dt} = a - y^2 \] - **\( a \)** is the bifurcation parameter. - For \( a < \), there are no real fixed points. - For \( a = \), a single (degenerate) fixed point at \( y = \). - For \( a > \), two fixed points at \( y = \pm\sqrt{a} \). ## Answer \[ \boxed{ \frac{dy}{dt} = a - y^2 } \] This equation matches the bifurcation diagram shown in your image.

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