VIPSolutions logo ✨ VIPSolutions

¥ ie — 01:29:26 = | EEE | rE : E 3 |= $3353 —— IR | fee fsteds _— 4 | Co—— 52805 i | i E 4 B-

Question:

Uploaded Image¥ ie — 01:29:26 = | EEE | rE : E 3 |= $3353 —— IR | fee fsteds _— 4 | Co—— 52805 i | i E 4 B-

This is AI generated Response.
Asked by: Veera manikanta
Created at: 2025-09-01 17:42:04

Final Answer:

Rendered Raw Text
Did you like this answer?
The question is: "Consider a rectangular tank which is 6 m long, 4 m wide, and 2 m high is floating in a fluid of density ρ. The rectangular tank is placed such that the length 6 m (height) is held vertically and the depth of immersion of the rectangular tank is 4 m. The rectangular tank is in __________ equilibrium." Let's analyze: - The tank's height is **2 m**. However, it's placed such that the **length (6 m) is vertical**, so the "height" is now 6 m. - The **depth of immersion is 4 m** (so, 4 m of the 6 m vertical side is underwater). - The stability of floating bodies depends on the **metacentric height (GM)**: - If GM > 0, **stable** equilibrium. - If GM = 0, **neutral** equilibrium. - If GM < 0, **unstable** equilibrium. For a rectangular tank, when its longest dimension is vertical, the **center of gravity is higher** and the **center of buoyancy is lower**, making the tank **unstable**. **Correct Answer:** The rectangular tank is in **unstable** equilibrium. So, the answer is: > Unstable If you have any specific calculations or want to see the reasoning in detail, let me know!

📢 Instructions:

  • Ask anything relatd to above question only.
  • For new Question goto :

Study Help, Fast Answers

VIPSolutions focuses on clear, step‑by‑step explanations so you can learn quickly. Whether you need an AI‑generated walkthrough or a short hint to get unstuck, each solution is organized for fast reading and easy review later.

Search similar questions, compare approaches, and bookmark the best answers for revision. Our goal is simple: quick, reliable study help that feels natural—not noisy.