egg Compt eee 01:28:10 — == Question 10 © k : . 2 Rap cooked 1 50 °C, held for 10000 secs, an n E: 3 | Seek mermwcoin A pecimen begins at 760° C and held og om . ous ssstanic scion R. he -. = I { 0% see i BE 0% ee 3 pon 50 a L. Gri 2 nd
Question:
egg Compt eee 01:28:10 —
== Question 10 © k
: .
2 Rap cooked 1 50 °C, held for 10000 secs, an n E:
3 | Seek mermwcoin A pecimen begins at 760° C and held og om . ous ssstanic scion R.
he -. =
I { 0% see i
BE 0% ee 3
pon 50 a
L. Gri
2 nd
This is AI generated Response.
Asked by: Veera manikanta
Created at: 2025-08-19 14:01:06
Asked by: Veera manikanta
Created at: 2025-08-19 14:01:06
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Let's break down the question step by step:
**Question:**
Consider an iron carbon alloy of eutectoid composition. While doing heat treatment, the following time-temperature treatment is done:
1. Rapidly cooled to 500°C, held for 5 seconds,
2. Rapidly cooled to 300°C, held for 10,000 seconds,
3. Quenched to room temperature.
Assume the specimen begins at 760°C (austenite).
**Ask:**
Specify the nature of the final microstructure.
---
### **Analysis:**
- **Austenite at 760°C:**
The alloy is fully austenitic.
- **Rapid cooling to 500°C and held for 5 seconds:**
This is too short for significant transformation, so mostly still austenite.
- **Rapid cooling to 300°C and held for 10,000 seconds:**
At 300°C, bainite forms if held for enough time. 10,000 seconds is sufficient for austenite to fully transform to bainite at this temperature.
- **Quench to room temperature:**
Anything left as austenite would transform to martensite, but since 10,000 seconds at 300°C is enough for complete bainite transformation, there should be no austenite left.
---
### **Conclusion:**
The **final microstructure** will be **100% bainite**.
---
### **Correct Answer:**
**100% bainite.**
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