VIPSolutionsEE ©. Them fb] Moodie Comps a pring Cone) Tnitielly velocity of blaks © zo; One the sping veaches ib'4 patimam conp ie vad, velodity again 20 Mens chauge in Kintic energy of bled 4 Zo = KA: = akey + 2KE, + Mag shy + My g 2h, = fe = 040 4 10x10 % Dy Smal — 20 X0X Armas Arar = 165-8 mm re] Maximum veladfy oF dod Bb (Vou) Oceurs , when change id KE do bloks equal 7 chauge in PE 4 blacks of ves of ow PRT TOE on spun Jae aids in metio te during tibial odmsion Vea. + Ms Vis, = 1g q Bg = Mpg Ag mtd 0 Vit, + 20 ae = 20x10 x(F0x15)- ies FOX[G X Smo 15 Vig =~ 9.9897 Via, = 0-14 1/422 ou
Question:
EE ©. Them
fb] Moodie Comps a pring Cone)
Tnitielly velocity of blaks © zo; One the sping
veaches ib'4 patimam conp ie vad, velodity again 20
Mens chauge in Kintic energy of bled 4 Zo
= KA: = akey + 2KE, + Mag shy + My g 2h,
= fe = 040 4 10x10 % Dy Smal — 20 X0X Armas
Arar = 165-8 mm
re] Maximum veladfy oF dod Bb (Vou)
Oceurs , when change id KE do bloks equal 7
chauge in PE 4 blacks of ves of ow PRT TOE
on spun Jae aids in metio te during tibial
odmsion
Vea. + Ms Vis, = 1g q Bg = Mpg Ag mtd
0 Vit, + 20 ae = 20x10 x(F0x15)- ies
FOX[G X Smo
15 Vig =~ 9.9897
Via, = 0-14 1/422
ou
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Asked by: Md Israrul Haque
Created at: 2025-10-20 15:44:05
Asked by: Md Israrul Haque
Created at: 2025-10-20 15:44:05
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# Summary of the Notes on Spring Compression and Block Velocity
## [b] Maximum Compression at Spring (Amax)
- Initial velocity of blocks is zero.
- When the spring reaches maximum compression, velocity becomes zero again.
- Change in kinetic energy (KE) is converted into elastic potential energy (EPE### Key Equation:
\[ \frac{1}{2} K \Delta x_{max}^2 = \Delta KE + \Delta PE + \text{Magnetic work} \]
- Given data:
- \(\Delta x_{max} = 165.8 \text{ mm}\)
---
## [c] Maximum Velocity of Block B (\(V_{max}\))
- Occurs when the change in KE of block A equals the change in PE of block B.
- During initial extension, spring force acts on the blocks.
### Energy conservation equation:
\[
\frac{1}{2} m_A V_{max}^2 + \frac{1}{2} m_B V_{max}^2 = m_B g \Delta e - m_A g \Delta e \sin^2 \theta
\]
### Calculation:
- \(V_{max}^2 = 8.2899\)
- \(V_{max} = .74 \text{ m/sec}\)
---
## Notes:
- The calculations involve energy transformations during spring compression.
- The maximum velocity is derived considering the energy balance between kinetic and potential energies.
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