## Problem Analysis The problem involves finding the bias point for a common-emitter (CE) amplifier circuit to achieve the maximum possible magnitude of the output sine wave. The circuit operates with: - A DC supply voltage \( V_{CC} = +3 \, \text{V} \) - An input sine-wave signal \( v_{be} \) with a peak amplitude of \( 5 \, \text{mV} \) ### Goal Determine: 1. The correct \( V_{CE} \) bias point. 2. The peak amplitude of the output sine wave. 3. The gain of the amplifier. ### Solution Approach 1. **Biasing for Maximum Swing**: - To maximize the output swing, the transistor should be biased at the midpoint of the load line. This typically places \( V_{CE} \) at \( V_{CC}/2 \). 2. **Calculate \( V_{CE} \)**: - \( V_{CE} = \frac{V_{CC}}{2} = \frac{3 \, \text{V}}{2} = 1.5 \, \text{V} \) 3. **Output Peak Amplitude and Gain**: - If the gain \( A_v \) is known, the output amplitude \( V_{out} \) can be calculated as: \[ V_{out} = A_v \times V_{in} \] - Assuming a gain \( A_v = -90 \, \text{V/V} \) (as per the hint), we calculate: \[ V_{out} = -90 \times 5 \, \text{mV} = -.45 \, \text{V} \] ### Conclusion - **Peak Amplitude of Output**: \( .45 \, \text{V} \) - **Gain**: \(-90 \, \text{V/V}\) These values align with the given hint, confirming the biasing and calculations are correct.