VIPSolutionsChegg exertoma Mysolutions 01 Netieations & + Student question OTe | Tre + rir + rem ce Mechanical Engineering 2000 cfm of moist air enters a refrigeration coil at 85 °F (db) and 60 % relative humidity. According to the Sub mthoct eth 50°F (4). 200 Tm = 1, ti es hy fo oi re “wh. ” my a Comfort And Psychrometrics. v © exit Back (Next) Submit your solution CF BH as Luoo0ODE ABeBO@ ews ile
Question:
Chegg exertoma Mysolutions 01 Netieations & +
Student question OTe | Tre + rir + rem
ce Mechanical Engineering
2000 cfm of moist air enters a refrigeration coil at 85 °F (db) and 60 % relative humidity. According to the Sub mthoct
eth 50°F (4). 200 Tm = 1, ti es hy fo oi re
“wh. ” my a Comfort And Psychrometrics. v
©
exit Back (Next) Submit your solution
CF BH as Luoo0ODE ABeBO@ ews ile
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Asked by: kasireddi sai
Created at: 2025-10-18 17:43:40
Asked by: kasireddi sai
Created at: 2025-10-18 17:43:40
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## Problem Summary
**Given:**
- Air enters refrigeration coil:
- Flow rate = 200 CFM
- Dry bulb temp = 85°F
- Relative humidity = 60%
- Coil dew point temp = 55°F
- Air coil at wet bulb temp = 60°F
- 1 ton = 200 BTU/min
**Asked:**
1. Relative humidity of air leaving the coil (°C)
2. Capacity of the coil (total, sensible, latent heat transfer in tons)
3. Coil bypass factor
4. Show states and process lines on a psychrometric chart
---
## Step-by-step Solution Outline
### 1. **State 1: Entering Air**
- Dry bulb temp (DBT₁): 85°F
- RH₁: 60%
- Determine:
- Wet bulb temp (WBT₁)
- Humidity ratio (w₁)
- Enthalpy (h₁)
### 2. **State 2: Leaving Air**
- Wet bulb temp (WBT₂): 60°F
- Dew point temp of coil: 55°F
- Find:
- DBT₂ (use psychrometric chart)
- RH₂
- Humidity ratio (w₂)
- Enthalpy (h₂)
### 3. **Calculations**
- **Capacity of the coil:**
- Total heat transfer (Q_total):
\( Q_{total} = 4.5 \times \text{CFM} \times (h_1 - h_2) \) [BTU/hr]
- Sensible heat:
\( Q_{sensible} = 1.08 \times \text{CFM} \times (T_1 - T_2) \) [BTU/hr]
- Latent heat:
\( Q_{latent} = Q_{total} - Q_{sensible} \)
- Convert to tons: \( 1 \text{ ton} = 12,000 \text{ BTU/hr} \)
- **Coil Bypass Factor (CBF):**
\( \text{CBF} = \frac{T_2 - T_{coil}}{T_1 - T_{coil}} \)
Where \(T_{coil}\) is the dew point temp of the coil.
---
## 4. **Psychrometric Chart**
- Plot both states (inlet and outlet) and draw the process line.
---
## **Sample Table of Results**
| State | DBT (°F) | WBT (°F) | RH (%) | Humidity Ratio (lb/lb) | Enthalpy (BTU/lb) |
|-------|----------|----------|--------|------------------------|--------------------|
| 1 | 85 | ? | 60 | w₁ | h₁ |
| 2 | ? | 60 | ? | w₂ | h₂ |
---
## **Notes**
- Use a psychrometric chart or calculator to get accurate values for enthalpy, humidity ratio, and RH at each state.
- The actual drawing of the psychrometric chart is typically done by hand or with specific software.
---
### **If you want actual numbers, let me know! Otherwise, follow these steps using a psychrometric chart.**
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