Ch 01% CC — 01:28:17 B

EE Queston 7 © k.
Ce. RL Sa
: = 07 Alowatie stem of 35 percentage.
2 =
T—. E
4 z
| ET ar
== -
==
- 3
3 =

BE. i
Pr - i” F
is Gin pe

Question

Ch 01% CC — 01:28:17 B

EE  Queston 7 © k.
Ce. RL Sa
: = 07 Alowatie stem of 35 percentage.
2 =
T—. E
4 z
| ET ar
== -
==
- 3
3 =

BE. i
Pr - i” F
is Gin pe

VIPSolutions · Accepted Answer

Let's analyze and solve the problem step by step:

**Given:**
- Initial diameter of the shell ($D_{initial}$) = **180 mm**
- Allowable strain ($\epsilon_{allowable}$) = **35%** = **0.35**

**Strain Definition:**
$$
\text{Strain} = \frac{\text{Change in diameter}}{\text{Original diameter}} = \frac{D_{final} - D_{initial}}{D_{initial}}
$$

**Rearrange to solve for $D_{final}$:**
$$
0.35 = \frac{D_{final} - 180}{180}
$$
$$
0.35 \times 180 = D_{final} - 180
$$
$$
63 = D_{final} - 180
$$
$$
D_{final} = 180 + 63 = 243 \text{ mm}
$$

**Answer:**  
The maximum diameter to which the shell can be expanded is **243 mm**.

So, the correct option is:
- **243 mm**

✨ VIPSolutions

Ch 01% CC — 01:28:17 B EE Queston 7 © k. Ce. RL Sa : = 07 Alowatie stem of 35 percentage. 2 = T—. E 4 z | ET ar == - == - 3 3 = BE. i Pr - i” F is Gin pe

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