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Question:
Bim en
Ee
led
EB ie oo se csr rent on UO
ERE
=
Cs SUSE
| mg be heh 1 cement in rss se ber amen he ues bo You
E Tre
If =
| ft ten
ee eee IE
Be roar cometh
Hl res
This is AI generated Response.
Asked by: Sunitha
Created at: 2025-10-20 11:08:31
Asked by: Sunitha
Created at: 2025-10-20 11:08:31
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# Analysis of Covid-19 Test Results
## Key Points:
- The test's **accuracy** varies depending on the true infection status.
- The **probability** that a person is infected given a positive test is called the **positive predictive value**.
- The **prob** that a person is not infected given a negative test is called the **negative predictive value**.
---
## Given Data:
| | Test Positive | Test Negative | Total |
|-------------------|-----------------|-----------------|---------|
| Infected | .01 | .2 | .5 |
| Not Infected | .001 | .5 | |
| **Total** | | | 1. |
---
## (a) Probability the person is infected given a positive test
### Calculation:
\[
P(\text{Infected} | \text{Test Positive}) = \frac{P(\text{Test Positive} | \text{Infected}) \times P(\text{Infected})}{P(\text{Test Positive})}
\]
Where:
\[
P(\text{Test Positive}) = P(\text{Test Positive} | \text{Infected}) \times P(\text{Infected}) + P(\text{Test Positive} | \text{Not Infected}) \times P(\text{Not Infected})
\]
Plugging in the values:
\[
P(\text{Test Positive}) = .01 \times .5 + .001 \times .5 = .005 + .0005 = .0055
\]
Now:
\[
P(\text{Infected} | \text{Test Positive}) = \frac{.01 \times .5}{.0055} = \frac{.005}{.0055} \approx .909
\]
**Answer:** The probability the person is infected given a positive test is approximately **90.9%**.
---
## (b) Probability the test yields a positive result in this community
### Calculation:
\[
P(\text{Test Positive}) = .0055
\]
**Answer:** The probability the test yields a positive result is **.55%**.
---
## Summary:
- **Probability infected given positive test:** **~90.9%**
- **Probability positive test in the community:** **.55%**
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