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3 Charging on the Side [15 Points] Probes: The chook blow cess of a capacitor C, aly charged, connected fo 3 battery of oka £ vin to stor A, ae. A ie 0, the switch coe { E i I 3 n Tn 10 QU) dente the charge te app (i peste) pie of the capacitor he disgram abene: (6) 5 Polonia] Wit down al depend eqstion rom Kishbol's res for this cet ern ot Tn. Lc al Q 0) 6 Poot] Osi the dificil cation obey the charge (1) on the capacitor by clini in, dT roms the xaos Gnd 1 eet (o) fn favor of XC) and S31 6) 5 Ponta) Dewitt oct tht the two estos are hen seis oe pete, he diffi cqustion rom ort (1) inf cay oe for Lt fot a gi RC leit deco in cure Cumpate th charg QU) on he posi lt of he capacitor anton of toe > 0 wel SRC cunt I) an r) hvngh ht eo 2

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Uploaded Image3 Charging on the Side [15 Points] Probes: The chook blow cess of a capacitor C, aly charged, connected fo 3 battery of oka £ vin to stor A, ae. A ie 0, the switch coe { E i I 3 n Tn 10 QU) dente the charge te app (i peste) pie of the capacitor he disgram abene: (6) 5 Polonia] Wit down al depend eqstion rom Kishbol's res for this cet ern ot Tn. Lc al Q 0) 6 Poot] Osi the dificil cation obey the charge (1) on the capacitor by clini in, dT roms the xaos Gnd 1 eet (o) fn favor of XC) and S31 6) 5 Ponta) Dewitt oct tht the two estos are hen seis oe pete, he diffi cqustion rom ort (1) inf cay oe for Lt fot a gi RC leit deco in cure Cumpate th charg QU) on he posi lt of he capacitor anton of toe > 0 wel SRC cunt I) an r) hvngh ht eo 2

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Asked by: Sahab Sharan
Created at: 2025-10-24 20:08:29

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Certainly! Here's a breakdown and explanation of the problem related to charging on the side of a capacitor: --- # Charging on the Side of a Capacitor ## Circuit Description - The circuit includes: - A voltage source \( \varepsilon \) - Two resistors: \( R_1 \) (connected in series with the voltage source) and \( R_2 \) (connected in parallel with the capacitor) - A capacitor \( C \) - The switch is initially open and closes at \( t = \) ## Key Variables - \( Q(t) \): Charge on the upper plate of the capacitor at time \( t \) - \( I_{R_1} \): Current through resistor \( R_1 \) - \( I_{R_2} \): Current through resistor \( R_2 \) - \( I_C \): Current through the capacitor --- ## Tasks and Points Breakdown ### (a) Write the independent equations (3 points) - Apply Kirchhoff's rules to derive equations governing the circuit - These equations relate \( Q(t) \), \( I_{R_1} \), \( I_{R_2} \), and \( I_C \) ### (b) Differential equation of charge \( Q(t) \) (5 points) - Derive the differential equation governing \( Q(t) \) based on the circuit's configuration - Use the relationships from Kirchhoff's laws and the capacitor charge-voltage relation \( Q = C V \) ### (c) Initial conditions and solving the differential equation (5 points) - Determine initial conditions (e.g., \( Q() \)) - Solve the differential equation to find \( Q(t) \) ### (d) Currents \( I_{R_1} \) and \( I_{R_2} \) (5 points) - Find \( I_{R_1}(t) \) and \( I_{R_2}(t) \) as functions of time - Use the solutions for \( Q(t) \) and circuit laws --- **Note:** You will need to apply Kirchhoff's voltage law (KVL) and Kirchhoff's current law (KCL), along with the capacitor relation \( I_C = \frac{dQ}{dt} \), to derive and solve the equations.

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