2) Calculate factor of safety of the retaining wall below against overturning, sliding and bearing capacity. \ \ < I B ~ SO A ! [ Shno \ / ¢-3au id | Xz 120 PCy | | VE | —/ \ A JJ MN | "A 9 [c 1.8 ’ \ Vv — — : - > 13 SARD ¢ 38 N =\wo fee
Question:
2) Calculate factor of safety of the retaining wall below against overturning, sliding and bearing
capacity.
\
\
< I B ~ SO
A
! [
Shno
\ / ¢-3au
id | Xz 120 PCy
|
|
VE | —/
\
A JJ MN | "A
9 [c 1.8 ’ \
Vv —
— : - >
13
SARD
¢ 38
N =\wo fee
This is AI generated Response.
Asked by: Test User 100005
Created at: 2025-05-12 09:02:07
Asked by: Test User 100005
Created at: 2025-05-12 09:02:07
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Let's break down the problem step by step:
### Given Data
- **Wall height (h):** 18 ft (above base), 2 ft (below base)
- **Base width (b):** 13 ft
- **Top width:** 1 ft
- **Toe:** 1.5 ft
- **Heel:** 1.5 ft
- **Thickness of base:** 1 ft
- **Soil Properties (behind wall):**
- φ = 34°, γ = 120 pcf (above base)
- **Soil Properties (below base):**
- φ = 32°, γ = 110 pcf
We will **ignore wall self-weight** unless otherwise asked (since material is not specified). Typically, you'd add the weight of the wall for a more accurate calculation.
---
## 1. **Calculate Lateral Earth Pressure (Active)**
We use **Rankine's Active Earth Pressure**:
\[
K_a = \tan^2 \left(45^\circ - \frac{\phi}{2}\right)
\]
For φ = 34°:
\[
K_a = \tan^2(45^\circ - 17^\circ) = \tan^2(28^\circ) \approx (0.5317)^2 \approx 0.282
\]
\[
P_a = \frac{1}{2} K_a \gamma h^2
\]
\[
P_a = \frac{1}{2} \cdot 0.282 \cdot 120 \cdot (18)^2
\]
\[
= 0.141 \cdot 120 \cdot 324
\]
\[
= 0.141 \cdot 38,880
\]
\[
= 5,482 \text{ lb/ft (per ft length of wall)}
\]
**Point of action**: \( h/3 \) from base (i.e., 6 ft above base).
---
## 2. **Weight of Soil Above Heel (Resisting Weight)**
Dimension: 1.5' (heel) × 18' (height) × 1 ft (length)
\[
W_{heel} = 1.5 \times 18 \times 120 = 3,240 \text{ lb/ft}
\]
**Distance from toe:** \( 1.5/2 = 0.75 \) ft from back face + 1 ft (thickness at top) = 1.75 ft from back face; so from toe: \( 1.5 + 1.5 + 1 = 4 \) ft (total base width left to right).
## 3. **Weight of Soil Above Toe**
Dimension: 1' (toe) × 2' (height) × 1' (length)
\[
W_{toe} = 1 \times 2 \times 110 = 220 \text{ lb/ft}
\]
---
## 4. **Weight of Soil Above Base (Middle Section)**
Dimension: 10' (middle) × 1' (base thickness) × 110 = 1,100 lb/ft
---
## 5. **Weight of Wall (if concrete, γ ≈ 150 pcf)**
Assume wall thickness is average (1.5 ft heel + 1 ft stem + 1.5 ft toe) = 4 ft × height 18 ft × γ (if needed).
---
## 6. **Moments Calculation (Overturning & Resisting)**
- **Overturning Moment, \(M_{OT}\):** \( P_a \times \frac{h}{3} \)
- **Resisting Moment, \(M_{R}\):** \( \sum W_i \times x_i \)
---
## 7. **Factor of Safety Calculations**
### **A. Overturning**
\[
FS_{OT} = \frac{M_{R}}{M_{OT}}
\]
### **B. Sliding**
\[
FS_{sliding} = \frac{\text{Resisting force}}{\text{Sliding force}}
\]
Resisting force = \( (\sum W) \tan \phi \)
### **C. Bearing Capacity**
Check eccentricity \( e \), ensure resultant falls within middle third. Bearing pressure:
\[
q_{max} = \frac{W}{B} \left(1 + \frac{6e}{B}\right)
\]
\[
q_{min} = \frac{W}{B} \left(1 - \frac{6e}{B}\right)
\]
---
## 8. **Plug in Numbers**
### **A. Overturning**
- \( P_a = 5,482 \text{ lb/ft} \)
- Overturning moment arm = 6 ft
- \( M_{OT} = 5,482 \times 6 = 32,892 \text{ lb-ft} \)
- Resisting moment (sum moments of all weights about toe).
---
### **Weight Calculations**
- Heel soil: \( W_{heel} = 3,240 \) lb/ft, arm = 1.5 ft (from toe)
- Toe soil: \( W_{toe} = 220 \) lb/ft, arm = 12.5 ft (from toe)
- Base soil: \( W_{base} = 1,100 \) lb/ft, arm = 7.5 ft (from toe)
\[
M_{R} = (3,240 \times 1.5) + (220 \times 12.5) + (1,100 \times 7.5) = 4,860 + 2,750 + 8,250 = 15,860 \text{ lb-ft}
\]
---
### **B. Sliding**
Total weight resisting = \( 3,240 + 220 + 1,100 = 4,560 \) lb/ft
Resisting force = \( 4,560 \times \tan 32^\circ \approx 4,560 \times 0.624 = 2,847 \) lb/ft
Sliding force = \( P_a = 5,482 \) lb/ft
\[
FS_{sliding} = \frac{2,847}{5,482} \approx 0.52
\]
---
### **C. Bearing Capacity**
Total weight = \( 4,560 \) lb/ft
Eccentricity, \( e = \frac{M_R - M_{OT}}{W} = \frac{15,860 - 32,892}{4,560} = -3.74 \) ft (negative means resultant is towards the heel).
Check \( e < B/6 = 13/6 = 2.17 \) ft. If not, there's a risk of tension at the toe.
---
## **Summary Table**
| Failure Mode | Factor of Safety | Criteria |
|------------------|------------------|----------------|
| Overturning | \( = \frac{M_R}{M_{OT}} = \frac{15,860}{32,892} = 0.48 \) | > 2.0 |
| Sliding | \( = 0.52 \) | > 1.5 |
| Bearing Capacity | (Check \( e \)) | \( e < B/6 \) |
---
## **Conclusion**
- **FS against overturning and sliding are both < 1**, which is **unsafe**. The wall needs to be redesigned (increase base width, add key, increase wall weight, etc.).
- **FS against bearing capacity** is also questionable due to excessive eccentricity.
**If you want to include the wall weight, or need a more detailed or different calculation, please specify the wall material or any additional data!**
---
**Let me know if you need calculations including the weight of the concrete wall or any other specifics!**
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