VIPSolutions01:17:00 — ug Question 11 . @ ed vino ee ny . Ma EE thecomesponding sar, 2Uon temperatyrey « pl oe 1237 0 an these "7 Soro i 73g pad oe = Sos POTAIor and condenserpres res Alsg dh actual COB ofa oie ® i. @ i. = @® AS 5c 4 a = On samicor,_-4 = i = ji “ill be 3 3 #3 Rusat An. sae ii = en -—
Question:
01:17:00 —
ug Question 11 .
@ ed vino ee ny . Ma EE
thecomesponding sar, 2Uon temperatyrey « pl oe 1237 0 an these "7 Soro i 73g pad oe
= Sos POTAIor and condenserpres res Alsg dh actual COB ofa oie
® i.
@ i.
=
@® AS
5c 4 a
= On samicor,_-4 =
i = ji “ill
be 3
3 #3 Rusat An. sae
ii =
en
-—
This is AI generated Response.
Asked by: Veera manikanta
Created at: 2025-08-16 15:58:09
Asked by: Veera manikanta
Created at: 2025-08-16 15:58:09
Final Answer:
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The question in the image asks:
**"Dry saturated vapor enters the condenser of an ammonia refrigerator at 12.37 bar and the pressure in the evaporator is 1.738 bar. Find the ideal COP operating between the corresponding saturation temperatures at the corresponding evaporator and condenser pressures. Also, find the actual COP of the cycle operating between same pressure limits."**
It then provides multiple-choice answers:
1. COP<sub>ideal</sub> = 3.6 and COP<sub>actual</sub> = 3.0
2. COP<sub>ideal</sub> = 11.6 and COP<sub>actual</sub> = 11.0
3. **COP<sub>ideal</sub> = 8.6 and COP<sub>actual</sub> = 8.6** (this is selected)
4. COP<sub>ideal</sub> = 4.6 and COP<sub>actual</sub> = 4.0
---
### Explanation
To solve this, you need to:
1. **Find the saturation temperatures** at 12.37 bar and 1.738 bar for ammonia (NH₃), usually from steam tables or thermodynamic property charts.
2. **Calculate the ideal COP** for a refrigerator:
\[
COP_{ideal} = \frac{T_{evap}}{T_{cond} - T_{evap}}
\]
where temperatures are in Kelvin.
3. **Estimate the actual COP** (typically lower than ideal, but sometimes the question may approximate them as equal if no losses are considered).
---
### Answer
The selected answer is:
- COP<sub>ideal</sub> = 8.6 and COP<sub>actual</sub> = 8.6
This would be correct **if the cycle is ideal and there are no irreversibilities** (theoretical scenario). For real cycles, COP<sub>actual</sub> is usually less than COP<sub>ideal</sub>.
If the question is about an ideal cycle and asks for COP between the given pressure limits (and if both are the same due to ideal assumptions), then the selected answer makes sense.
---
**Summary:**
The answer selected in the image is:
- **COP<sub>ideal</sub> = 8.6 and COP<sub>actual</sub> = 8.6**
If you need a step-by-step calculation or need clarification on how to use property tables, let me know!
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